Answer:
Percent mass of KNO3 in solution = 11% (Approx)
Explanation:
Given:
Mass of KNO3 = 25 grams
Mass of H2O = 200 grams
Find:
Percent mass of KNO3 in solution
Computation:
Mass of solution = 25 + 200 = 225 grams
Percent mass of KNO3 in solution = [25/225]100
Percent mass of KNO3 in solution = 11.111%
Percent mass of KNO3 in solution = 11% (Approx)
Answer:
Explanation:
Glucose has a chemical formula of: C6H12O6 That means glucose is made of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms.
The balanced equation for the reaction is as follows
2RbNO₃ --> 2RbNO₂ + O₂
stoichiometry of RbNO₃ to O₂ is 2:1
number of moles of RbNO₃ decomposed - 5.0 mol
when 2 mol of RbNO₃ decomposes, 1 mol of O₂ is formed
therefore when 5.0 mol of RbNO₃ decomposes - 5.0 / 2 = 2.5 mol of O₂
2.5 mol of O₂ is formed
Frequency = speed of light/ wavelength of photon. wavelength = speed of light/frequency = 3 x 10^8 / 2.43 x 10^8= 1.23m
Answer:
New volume, V2 = 15mL
Explanation:
Given the following data;
Initial volume, V1 = 30mL
Initial pressure, P1 = 4atm
New pressure, P2 = 8atm
To find the new volume V2, we would use Boyles' law.
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
Substituting into the equation, we have;
V2 = 15mL
<em>Therefore, the new volume is 15 mL. </em>