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polet [3.4K]
3 years ago
15

Combustibles fosiles ¿Por qué son inflamables los gases naturales?¿Dónde están los gases naturales?¿Cómo podemos sacar el aceite

?¿Dónde está el carbón?¿Es el combustible fósil una fuente no renovable? AYUDAA
Chemistry
1 answer:
Kitty [74]3 years ago
8 0

Answer:

1) Los gases naturales son inflamables porque el natural contiene metano junto con una pequeña cantidad de otros gases orgánicos, lo que hace que una mezcla de entre 5 y 15% de concentración de gas natural con aire u oxígeno se queme por completo cuando se enciende.

2) El petróleo crudo, que son depósitos de hidrocarburos que se encuentran en depósitos naturales en las formaciones subterráneas de la Tierra, se obtiene perforando un pozo en el yacimiento de petróleo a través del cual se permite que una parte importante del petróleo fluya fuera del yacimiento bajo la presión del yacimiento para recibir procesamiento e instalaciones de almacenamiento en la superficie

3) El carbón se forma cuando se aplica compactación y calor a la turba que proviene de material vegetal muerto enterrado durante un período de varios millones de años.

4) Los combustibles fósiles se consideran una fuente de combustible no renovable porque la velocidad a la que se produce es más rápida que la velocidad a la que se forma.

Una fuente de energía renovable, como la energía eólica, es producida por la naturaleza tan rápido como se consume para generar energía.

Explanation:

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Fluorides of the relatively unreactive noble gas xenon can be formed by direct reaction of the elements at high pressure and tem
trasher [3.6K]

Answer:

Mass percent XeF₄: 13.78%

Mass percent XeF₆: 86.22%

Explanation:

Moles of Xe are equal to moles of XeF₄ + Moles XeF₆:

<em>Moles Xe:</em>

1.85x10⁻⁴mol - 9.00x10⁻⁶ mol = 1.76x10⁻⁴ moles Xe reacted:

1.76x10⁻⁴ moles = Moles of XeF₄ + Moles XeF₆ <em>(1)</em>

<em> </em>

Moles of F₂ = 1/2 Moles XeF₄ + 1/3 Moles XeF₆

5x10⁻⁴ = 2 Moles XeF₄ + 3 Moles XeF₆ (2)

Replacing (1) in (2):

5x10⁻⁴ = 2 Moles XeF₄ + 3 Moles XeF₆

5x10⁻⁴ = 2 (1.76x10⁻⁴ moles - 1 Mol XeF₆) + 3 Moles XeF₆

5x10⁻⁴ = 3.52x10⁻⁴ - 2 Mol XeF₆ + 3 XeF₆

1.48x10⁻⁴ = Mol XeF₆

And moles XeF₄:

Moles XeF₄ = 1.76x10⁻⁴ moles - 1.48x10⁻⁴ moles = 2.8x10⁻⁵ moles

In grams (Molar mass XeF₄: 207.28g/mol: XeF₆: 245.28g/mol):

Mass XeF₄: 2.8x10⁻⁵ mol * (207.28g / mol) = 5.8x10⁻³g

Mass XeF₆: 1.48x10⁻⁴ mol * (245.28g / mol) = 0.0363g

Mass percent XeF₄:

5.8x10⁻³g / (5.8x10⁻³g + 0.0363g) * 100 = 13.78%

Mass Percent XeF₆:

0.0363g / (5.8x10⁻³g + 0.0363g) * 100 = 86.22%

6 0
4 years ago
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