Sugar would not increase the boiling point of the water as much as the others.To show this, we recall the equation for boiling point elevation ∆t:
∆t = i Kb m
The difference in these four solutions will be in the product of the van't Hoff Factor i and molality m: i * m.
If we assume that we have 0.1m of each solute, the products i*m for these solutions are:
Solution Identity of particles i i * m
0.1 m NaCl Na+, Cl- 2 2 * 0.1 = 0.2
0.1 m MgSO4 Mg^2+, SO4^2- 2 2 * 0.1 = 0.2
0.1 m K2SO4 two K+, SO4^2- 3 3 * 0.1 = 0.3
0.1 m C12H22O11 covalently bonded molecules 1 1 * 0.1 = 0.1
Therefore, having the lowest i * m, sucrose will have the lowest boiling point elevation.
C.)Cool air near the surface forms high-pressure areas; warm air forms low-pressure areas.
Explanation:
The relationship between air temperature and high and low pressure air is such that cool air near the surface forms high-pressure areas and warm air forms low pressure areas.
- Cool air is closer to the surface because it has low kinetic energy to move. It is denser.
- Warm air rises sharply away from the ground surface.
- They form low pressure areas and their molecules are wide apart due to their high kinetic energy. The air is less dense.
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Kinetic energy brainly.com/question/9924094
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A mole is equivalent to 6.02 x 10^23 molecules at STP. Use a conversion factor like the following.
Example: The initial value x The value you are trying to convert to
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The value you are trying to get rid of
Answer:
not sure if this us right but oxygen and fluorine? I learned chem but I forgot about it kinda sorry
