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diamong [38]
3 years ago
12

Which of the following is an example of pure research? searching for fuels other than gasoline to power cars producing heat-resi

stant plastics for use in household ovens creating synthetic elements to study their properties finding ways to slow down the rusting of iron ships
Chemistry
1 answer:
Sliva [168]3 years ago
4 0
I think the correct answer would be the third option. An example of a pure research would be creating synthetic elements to study their properties. Pure research is also known as fundamental or basic research. It has an exploratory nature wherein it is done without any end use in mind. It is mostly out of the curiosity or intuition of a researcher. Most of the study under this type is aiming to advance an existing knowledge by explaining or identifying the relationship of the variables being studied. It is aimed at improving theories in order to the understanding of a specific  phenomenon. 
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Na + H2O -> NaOH +H2 stoichiometry?
Gemiola [76]

Answer:

Sodium + Water = Sodium Hydroxide + Dihydrogen

Explanation:

eaction of sodium with water

Sodium metal reacts rapidly with water to form a colourless solution of sodium hydroxide (NaOH) and hydrogen gas (H2). The resulting solution is basic because of the dissolved hydroxide. The reaction is exothermic.

4 0
3 years ago
When the equation below is correctly balanced, what are the coefficients of Pb and H20, respectively? Pb + H2O + O2 => Pb(OH)
stepan [7]

Answer:

C

Explanation:

Pb + H2O + O2 => Pb(OH)2

Number of oxygen atom on left = 3

Number of oxygen atom on the right = 2

To balance number of oxygen

Change the coefficient of Pb and H2O to two each

2Pb + 2H2O + O2 => 2Pb(OH)2

The coefficient of Pb and H2O is 2,2

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3 years ago
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3 years ago
How much heat is required to melt 26.0 g of ice at its melting point?
MAXImum [283]

Answer:

Heat required to melt 26.0 g of ice at its melting point is 8.66 kJ.

Explanation:

Number of moles of water in 26 g of water: 26× \frac{1}{18.02} moles

                                                                      =1.44 moles

The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol.

we have relation as:

                                           q = n × ΔH

where:

q  = heat

n  = moles

Δ H  = enthalpy

So calculating we get,

                                        q= 1.44*6.02 kJ

                                        q= 8.66 kJ

We require 8.66 kJ of energy to melt 26g of ice.

                       

8 0
3 years ago
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