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diamong [38]
3 years ago
12

Which of the following is an example of pure research? searching for fuels other than gasoline to power cars producing heat-resi

stant plastics for use in household ovens creating synthetic elements to study their properties finding ways to slow down the rusting of iron ships
Chemistry
1 answer:
Sliva [168]3 years ago
4 0
I think the correct answer would be the third option. An example of a pure research would be creating synthetic elements to study their properties. Pure research is also known as fundamental or basic research. It has an exploratory nature wherein it is done without any end use in mind. It is mostly out of the curiosity or intuition of a researcher. Most of the study under this type is aiming to advance an existing knowledge by explaining or identifying the relationship of the variables being studied. It is aimed at improving theories in order to the understanding of a specific  phenomenon. 
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Which species is oxidized in the reaction below? al2o3(s) 3 co(g) → 2 al(s) 3 co2(g)
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Al species is oxidized in the reaction below  al2o3(s) 3 co(g) → 2 al(s) 3 co2(g by oxidation

The reaction brought on by coming into touch with oxygen molecules is known as oxidation. These materials can be non-metals like live tissues or metals. Technically speaking, oxidation is the loss of one electron during the phase of interaction between two or more atoms.

Initially, the word "oxidation" was used to refer to chemical processes in which an element reacts with oxygen. An illustration of this is the oxidation of magnesium in the formation of magnesium oxide when magnesium metal and oxygen react.

The biological oxygen demand (BOD) of wastewater is decreased after oxidation, which also lessens some contaminants' toxicity. Some contaminants undergo this treatment and are transformed into carbon dioxide, water, and biosolids. Disinfection is commonly accomplished using chemical oxidation.

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8 0
2 years ago
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6 0
3 years ago
It is expected that a chemical reaction will occur when copper metal is combined with aqueous zinc sulfate. Explain why there wi
REY [17]

Answer:

E_{cell}= +ve, reaction is spontaneous

E_{cell}= -ve, reaction is non spontaneous

E_{cell}= 0, reaction is in equilibrium

Case 1: when copper metal is combined with aqueous zinc sulfate.

Cu+ZnSO_4\rightarrow Zn+CuSO_4

Here copper is undergoing oxidation ad thus acts as anode and zinc is undergoing reduction , thus acts as cathode.

E^o_{cell} = standard electrode potential =E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Cu^{2+}/Cu]}= +0.34V

E^0_{[Zn^{2+}/Zn]}= -0.76V

E^0=E^0_{[Zn^{2+}/Zn]}- E^0_{[Cu^{2+}/Cu]}

E^0=-0.76-(+0.34)=-1.10V

Thus as E_{cell} is negative , the reaction is non spontaneous.

Case 2: when zinc metal and aqueous copper sulfate solution are combined.

Zn+CuSO_4\rightarrow Cu+ZnSO_4

Here zinc is undergoing oxidation ad thus acts as anode and copper is undergoing reduction , thus acts as cathode.

E^o_{cell} = standard electrode potential =E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

E^0_{[Cu^{2+}/Cu]}= +0.34V

E^0_{[Zn^{2+}/Zn]}= -0.76V

E^0=E^0_{[Cu^{2+}/Cu]}- E^0_{[Zn^{2+}/Zn]}

E^0=+0.34-(-0.76)=+1.10V

Thus as E_{cell} is positive , the reaction is spontaneous.

3 0
4 years ago
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