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galina1969 [7]
2 years ago
10

Finding number of atoms 9H2SO4

Chemistry
1 answer:
Molodets [167]2 years ago
7 0

Explanation:

23 are the number of atoms

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The fourth option on Edgen, "two alcohol functional groups". You're welcome :)
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3 years ago
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Is a molecule positive or negative?
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It can be either they can have a negative or positive charge more specifically negatively charged molecule would called an anion and a positive one would be cation.

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2 years ago
34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

<em>ΔT is change in temperature = 11.21°C</em>

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0
2 years ago
How is a weak acid DIFFERENT from a dilute acid?
telo118 [61]
In a dilute acid solution most if not all of the molecules will split into ions.
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in a weak acid solution only a portion of the molecules will turn into ions because the ionization percentage isn't as large. Which will essentially leave a high percentage of un-reacted molecules
4 0
3 years ago
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7. If a waste container has 87.0 mL of 0.234 M acetic acid, how many milliliters of 2.00 M sodium
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Answer:

V_{base}=10.2mL

Explanation:

Hello.

In this case, since the neutralization of the acid requires equal number of moles of both acid and base:

n_{acid}=n_{base}

Whereas we can express it in terms of concentrations and volumes:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we can compute the volume of sodium hydroxide (base) as follows:

V_{base}=\frac{M_{acid}V_{acid}}{M_{base}} \\\\V_{base}=\frac{87.0mL*0.234M}{2.00M}\\ \\V_{base}=10.2mL

Best regards.

8 0
3 years ago
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