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3 years ago

How do the electron configurations for chlorine explain the steps pls

Chemistry

1 answer:

ryzh [129]3 years ago

7 0

Answer:

follow the steps

Explanation:

First make a circle and write 17p and 18n below 17 p.Now again make another circle bigger than previous one and make two small circle .Again make another bigger circle and fill it with 8 small circles .Again make another bigger circle than previous ones and make 7 small circles in it .Now write e in small circles .Then write

Chlorine

Atomic number=17

Atomic weight =35

Shell k l m n

no.of e .2 1 × ×

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Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

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$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

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Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

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Now put all the given values in the above formula, we get:

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$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

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