Let the mass of the person be m. Total momentum is conserved (because the exterior forces on the system are balanced), especially the component in the vertical direction.
Given that,
Mass of gallon is M
Let man mass be m
Velocity of man is v
Let velocity if ballot be Vb
When the person begin to move we have
Conservation of momentum
mv + MVb=0
MVb=-mv
Vb= -(m/M) v
Given that the mass of man is less than mass of balloon. i.e. m<M
So, if m<M, then, m/M <1
Therefore, .
Vb= -(m/M) v
Vb< -v
This implies that the velocity of balloon is less than the velocity of man and if is also moving in opposite direction
So the man is moving upward, then the balloon is moving downward and it's velocity is less than the velocity of man,
The answer is C
Down with a speed less than v
Answer:
300
Explanation:
i answered it and got it right
The speed of a satellite in a circular orbit around the Earth is 4,188 m/s.
<h3>Speed of the satellite</h3>
The speed of the satellite is calculated as follows;
v = √GM/r
where;
- M is mass of Earth
- r is radius of satellite
v = √[(6.67 x 10⁻¹¹ x 5.98 x 10²⁴) / (3.57 x 6.37 x 10⁶)]
v = 4,188 m/s
Thus, the speed of a satellite in a circular orbit around the Earth is 4,188 m/s.
Learn more about speed of satellite here: brainly.com/question/25721729
#SPJ1
Answer:
a)ω₂=127.64 rad/s ( min)
ω₁= 333.32 rad/s ( max)
b) At d₂= 11.75 cm ,ω₂=127.64 rad/s
d₁=4.5 cm,ω₁= 333.32 rad/s
c)α = 7.1 x 10⁻³ rad/s²
Explanation:
Given that
r₂= 11.75 cm
r₁=4.5 cm
v= 7.5 m/s
a)
We know that
v=ω r
ω =Angular speed
r= radius
v= velocity
When d₂= 11.75 cm :
v=ω r
7.5 x 2 =ω₂ x 0.1175
ω₂=127.64 rad/s ( min)
N₂=1219.4 rpm
When d₁=4.5 cm :
v=ω r
7.5 x 2=ω₁ x 0.045
ω₁= 333.32 rad/s ( max)
N₁=3184.58 rpm
The average angular acceleration α given as
ω₁ = ω₂ + α t
333.32 = 127.64 + α x 8 x 60 x 60
α = 7.1 x 10⁻³ rad/s²
<span>c. increases across a period and decreases down a group.</span>