As we know that total work done by a force is given by


so it is product of force and displacement along same direction
as we can write it as

so it must be the product of force and displacement in same directions so correct answer must be
<u>b. is parallel to the displacement of the object</u>
Distance is indeed a scalar amount that also refers to "<em><u>how the ground an object has encased</u></em>", and the Displacement is a vector thing that leads "<em><u>to the extent to which an object is located</u></em>", and the further calculation can be defined as follows:
Given:
distance= 70 miles
displacement = 20 miles
- Displacement formula:

- Distance formula:

Please find the graph in the attached file.
Learn more:
brainly.com/question/9290794
The wavelength, which represents the size of the smallest detectable detail that uses ultraviolet light , is calculated as follows: 3×
/ 1.72×
or approximately 1.74×
m.
The distance between the two positive, two negative, or two minimal points on the waveform is known as the wavelength of the wave. The following formula expresses the relationship between the frequency and wavelength of light:
f = c / λ
where, f = frequency of light
c = speed of light
λ = wavelength of light
Given data = f = 1.72×
Hz
Therefore, λ = 3×
/ 1.72×
λ = 1.74×
m
The wavelength, which represents the size of the smallest detectable detail that uses ultraviolet light , is calculated as follows: 3×
/ 1.72×
or approximately 1.74×
m.
Learn more about light here;
brainly.com/question/15200315
#SPJ4
Answer:
a) 
b)
c) 
d) Treat the humans as though they were points or uniform-density spheres.
Explanation:
Given:
- mass of Mars,

- radius of the Mars,

- mass of human,

a)
Gravitation force exerted by the Mars on the human body:

where:
= gravitational constant


b)
The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.


c)
When a similar person of the same mass is standing at a distance of 4 meters:


d)
The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.
- Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
- Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
Answer:
Both Technician A and Technician B
Explanation:
In order to gain a better understanding of the solution above let define some terms
Break Accumulator
We can define a break accumulator as storage that that helps generate the required pressure in order for the breaking system to respond faster this accumulator is charged by turning the steering wheel slowly at once from lock to lock now this build the pressure in the accumulator and one way to depressurize is it is by turning the ignition switch ""off""
Now a scan tool is a device that can interface with a car it can also be used to diagnose a car an get the diagnostic information to help in the cars diagnoses and also be used to reprogram a car