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Volgvan
3 years ago
11

What is the impact force on a 0.5 kg object if it falls 3 meters and hits a carpeted floor at 8 m/s, stopping in 0.10 seconds?

Physics
1 answer:
Cerrena [4.2K]3 years ago
4 0

the I'm pact force of 0.5 is lol u guys go and study why r u asking answers

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A fish in an aquarium with flat sides looks out at a hungry cat. To the fish, does the distance to the cat appear to be less tha
lakkis [162]

Answer:

p = -q  

he distance is equal to the current distance, so the distance does not change

Explanation:

For this exercise we can solve it using the equation of the constructor

            1 / f = 1 / p + 1 / q

where f is the focal length, p the distance to the object and q the distance to the image

For a flat surface the radius is at infinity, therefore 1 / f = 0, which implies

          1 / p = - 1 / q

           p = -q

Therefore the distance is equal to the current distance, so the distance does not change

7 0
3 years ago
Which of the following is true about the myelin sheath in a nerve cell?
Rzqust [24]
You didn’t write the options ‍♀️
5 0
3 years ago
Why is it important for a muscle to be attached to a fixed origin at one end and a moving insertion at the other? Discuss how th
vlabodo [156]
Muscles function only by contracting. This makes it necessary for one end of the muscle to be fixed and the other mobile.
Take the bicep for example.
Its origin is at the shoulder and its two heads connect to the bones of the forearm, the radius and ulna.
Now, had the muscle not been fixed at one end, and contracted, it would pull both our shoulder and forearm together resulting in an ineffective movement. The desired motion is to lift the forearm (proximal and distal movement) which can only be achieved if the bicep is fixed at the shoulder and allowed to move at the forearm.
6 0
3 years ago
Electrons are emitted from a surface when light of wavelength 500 nm is shone on the surface but electrons are not emitted for l
liberstina [14]

Explanation:

Given: \lambda = 500\:\text{nm} = 5×10^{-7}\:\text{m}

\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{5×10^{-7}\:\text{m}}

\:\:\:\:\:= 6×10^{14}\:\text{Hz}

The work function \phi is then

\phi = h\nu = (6.626×10^{-34}\:\text{J-s})(6×10^{14}\:\text{Hz})

\:\:\:\:\:\:\:= 3.98×10^{-19}\:\text{J}

3 0
3 years ago
A 66.5kg astronaut is doing a repair in space on the orbiting space station. She throws a 2.30kg tool away from her at 3.10m/s r
MrRa [10]

Answer:

Explanation:

mass of astronaut, M = 66.5 kg

mass of tool, m = 2.3 kg

velocity of tool, v = 3.10 m/s

Let the velocity of astronaut is V.

(A) According to the conservation of moemntum

Momentum of astronaut = Momentum of tool

M x V = m x v

66.5 x V = 2.3 x 3.10

V = 0.107 m/s

(B) The direction of motion of astronaut is opposite to the direction of motion of tool.

6 0
3 years ago
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