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Volgvan
3 years ago
11

What is the impact force on a 0.5 kg object if it falls 3 meters and hits a carpeted floor at 8 m/s, stopping in 0.10 seconds?

Physics
1 answer:
Cerrena [4.2K]3 years ago
4 0

the I'm pact force of 0.5 is lol u guys go and study why r u asking answers

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A published hypothesis:
kow [346]

Answer:

should be tested by the scientific community

4 0
3 years ago
Blood is more viscous than water. This is because it
JulijaS [17]

Answer:

Blood is thicker than water due primarily to the presence of red blood cells

Answer: <u>This is because it becomes more dense when cells are added</u>

Hope this helped :3

6 0
4 years ago
What will be the average velocity of a body falling in free fall on Earth for 3 s?
SpyIntel [72]

Answer:

29.4m/s

Explanation:

Given parameters:

Time  = 3s

Unknown:

Average velocity  = ?

Solution:

To solve this problem, we use the expression below:

      v  = u + gt

v is the average velocity

u is the initial velocity  = 0m/s

g is the acceleration due to gravity  = 9.8m/s²

t is the time

So;

        v  = 0 + (9.8 x 3)  = 29.4m/s

6 0
3 years ago
2) A 20 kg mass moving at a speed of 3 m/s is stopped by a constant force of 15 N. How many seconds must the force act on the ma
hammer [34]

Take the object's starting direction of motion to be the positive direction, so that a stopping force acts in the opposite direction. By Newton's second law, the object undergoes an acceleration <em>a</em> such that

-15 N = (20 kg) <em>a</em>

Solve for <em>a</em> :

<em>a</em> = - (15 N) / (20 kg) = -0.75 m/s²

The object's velocity <em>v</em> at time <em>t</em> is then given by

<em>v</em> = 3 m/s + (-0.75 m/s²) <em>t</em>

so the time it takes for the object to slow to a rest is

0 = 3 m/s + (-0.75 m/s²) <em>t</em>

<em>t</em> = (3 m/s) / (0.75 m/s²) = 4.0 s

3 0
3 years ago
A roller-coaster car has a mass of 1080 kg when fully loaded with passengers. As the car passes over the top of a circular hill
Dmitriy789 [7]

Answer:

(a): The normal force on the car  from the track when the car's speed is v= 7.6 m/s  is  FN= -6696 N.

(b): The normal force on the car from the track when the car's speed is v= 17 m/s is FN= 8912.7 N.

Explanation:

m= 1080 kg

r= 16m

v1= 7.6 m/s

v2= 17 m/s

g= 9.81 m/s²

v1= w1*r

w1= v1/r

w1= 0.475 rad/s

ac1= w1² * r

ac1= 3.61 m/s²

FN= m * (ac1 - g)

FN= -6696 N    (a)

-----------------------------------------------------

v2= w2*r

w2= v2/r

w2= 1.06 rad/s

ac2= w2² * r

ac2= 18.06 m/s²

FN= m * (ac2 - g)

FN= 8912.7 N    (b)

4 0
3 years ago
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