Answer:
Acceleration=115m/s²
Explanation:
speed=distance/time
23=120/time
/120 on both sides
0.2s is time
acceleration= change in velocity/time taken
23/0.2=115
acceleration=115m/s²
So i think that the question you are asking is the one of the exercise that says that the rope is very short and throws his bag also and you need to find the final speed of the bag tools. Well given the data we can use this next formulas to do this. First we are talking about conserve momentum: So we use a formula with the data like this:
<span>(135 + 13.0)kg * 1.50m/s = 135kg * V + 13.0kg * v </span>
<span>As we want V = 0; then </span>
<span>minimum v = 148kg * 1.50m/s / 13.0kg = 17.1 m/s
I hope is what you were looking for </span>
Answer:
-21.6 m/s^2
Explanation:
First of all, we need to convert the initial and final velocities into m/s:
is the initial velocity
is the final velocity
The acceleration is given by
where
t = 90 s is the time elapsed
Substituting the numbers, we find
and the negative sign means the rocket is decelerating.
We call it a "green" leaf because green light bounces off of it and enters our eyes. Other colors of light are absorbed by the leaf and stop right there.
If there's no green light to bounce off of the leaf, then no light at all comes from it.
When we look at an object that has no light coming from it, we describe the object as "black". We only know it's there because of its background and surroundings.
(Choice - A)
Opposite rays
From the term “opposite” which is derived from the Latin word
“oppositus” meaning “set against”, Opposite Rays are two rays which start from one
common point and is pointed outwards in an exact opposite direction from each
other forming a straight line.
<span>For example, this is Line A
<<<+========== ;
this is Line B ==========+>>></span>
Line A and Line B are two rays but they can only be called
Opposite Rays when they both start from a common point which is Letter O; thus,
forming a straight line.
A <<<+========== O
==========+>>> B
When there are opposite rays, points A, O, and B are
collinear, meaning these points are present in the same straight line.
