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seropon [69]
2 years ago
7

Subtract 6x^2-5x+3 from (3x^2+8x-4)

Mathematics
1 answer:
Art [367]2 years ago
8 0
3x^2 + 8x - 4 - (6x^2 - 5x + 3)....distribute thru the parenthesis
3x^2 + 8x - 4 - 6x^2 + 5x - 3 .....combine like terms
-3x^2 + 13x - 7 <==
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How many liters of water must be added to 15 liters of 40 % sugar syrup to obtain 30 % sugar syrup?
Ivanshal [37]

Answer:

The amount of water need to be added is 5 liters.

Step-by-step explanation:

Let's "x" be amount of water in (liters) added to 15 liters of 40% of sugar syrup.

Now find the amount of sugar syrup = 40% of 15

= 0.4 × 15

The amount of sugar syrup = 6 Liters

To dilute  30% we need to find amount of water to be added.

So,

30% of (15 + x) = 6

0.3 × (15 + x) = 6

4.5 + 0.3x = 6

0.3x = 6 - 4.5

0.3x = 1.5

Dividing both sides, by 0.3, we get

x = 5

So, the amount of water need to be added is 5 liters.

6 0
3 years ago
Read 2 more answers
Kate is going to purchase a coat for $38, pants for $45, and 2 pairs of shoes for $34 each. if she has $180 to spend how much mo
likoan [24]
She would have 20 dollars left over. take the amount of money she has then add up all of the cost of the stuff she will buy then subtract.
5 0
3 years ago
The output is one more than six times the input. Answer in this form y=mx+b
stepladder [879]
Y= 6x + 1.
6x represents six times, and the +1 is “one more.”
3 0
2 years ago
The square pyramid has a volume of 768 cubic inches. The height equals 1/6x and the base is just x. What is the value of x ?
Lunna [17]
The volume for a pyramid is V= \frac{1}{3} Bh, where B is the area of the base and h is the height.  We are given the volume, and the base and height in terms of x.  Our formula then looks like this: 768= \frac{1}{3} (x)( \frac{1}{6} x).  Simplifying the right side we have 768= \frac{1}{18}  x^{2}.  Multiply both sides by 18 to get rid of the fraction and we have 13824= x^{2}, so x = 117.575
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3 years ago
PLS HELP!! AND HURRY!! Find an expression for the nth term ( tn ) in each of the following sequences:
fiasKO [112]

If the pattern continues, so that each term is separated by a distance of 3, then the sequence is given by the recursive rule

\begin{cases}a_1=1\\a_n=a_{n-1}+3&\text{for }n>1\end{cases}

From this definition, we can write a_n in terms of a_1:

a_2=a_1+3

a_3=a_2+3=(a_1+3)+3=a_1+2\cdot3

a_4=a_3+3=(a_1+2\cdot3)+3=a_1+3\cdot3

a_5=a_4+3=(a_1+3\cdot3)+3=a_1+4\cdot3

and so on, up to

a_n=a_1+(n-1)\cdot3

(notice how the subscript on <em>a</em> and coefficient on 3 add up to <em>n</em>)

or

a_n=1+3(n-1)=3n-2

6 0
3 years ago
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