The prallelogram whose adjacent sides are equal and one vertex angle is 90 degrees is a square.
The value of angle 1 is 90 degrees as the diagonal of the square intersect at 90 degrees.
![\begin{gathered} 4y-2=90 \\ 4y=92 \\ y=23 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%204y-2%3D90%20%5C%5C%204y%3D92%20%5C%5C%20y%3D23%20%5Cend%7Bgathered%7D)
The value of y is 23.
The diagonal of the square bisect the vertex angle hence the angle of 3x is 45 degrees.
![\begin{gathered} 3x=45 \\ x=15 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%203x%3D45%20%5C%5C%20x%3D15%20%5Cend%7Bgathered%7D)
Thus, the value of x is 15 degrees.
The value of 12z is 45 degrees.
![\begin{gathered} 12z=45 \\ z=3.75 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2012z%3D45%20%5C%5C%20z%3D3.75%20%5Cend%7Bgathered%7D)
Thus, the required value of z is 3.75 degrees.
Not similar one is using a 20 in area and the other is using a 96 in area
<u>9x</u> = <u>3y + 5</u>
9 9
x = 1/3y + 5/9
x - 5/9 = 1/3y + 5/9 - 5/9
x - 5/9 = 1/3y
3(x - 5/9) = 1/3y · 3
3x - 1 2/3 = y
y = 3x - 1 2/3
1.5 meters
There is 30 cm in a foot and 5 feet times 30 is 150. There is 100 cm in a meter so 150/100 is 1.5 meters.
I am going to show you how easy this is. Once you understand, you will be able to do this forever.
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Assuming the side of the rectangle are (L) length and (W) width, the perimeter:
2L + 2W = 234
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"the rectangle is twice as long as it is wide,", the equation for this statement:
L = 2W
:
In the first equation, we can replace L with 2W, then we have
2(2W) + 2W = 234
4W + 2W = 234
6W = 234
Divide both sides by 6
W = 234%2F6
W = 39 meters is the width
:
Remember it said the length is twice the width, therefore:
L = 2(39)
L = 78 meters is the length
:
:
Check this by finding the perimeter with these values
2(78) + 2(39) =
156 + 78 = 234