I think you should combine like terms
Here the line passes through (0,0) and (1,3).
First we need to find the slope , and for that we need to use the following formula
![m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=%20m%3D%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D%20%20)
On substituting the values from the point, we will get
![m=\frac{3-0}{1-0}=3](https://tex.z-dn.net/?f=%20m%3D%5Cfrac%7B3-0%7D%7B1-0%7D%3D3%20%20)
Now we will use slope intercept form, which is
![y = mx+ b](https://tex.z-dn.net/?f=%20y%20%3D%20mx%2B%20b%20)
Where m is the slope and b is the y intercept
And on substituting the values of x and y from the point (1,3) and slope, m = 3, we will get
![3 = 3(1)+b](https://tex.z-dn.net/?f=%203%20%3D%203%281%29%2Bb%20)
![3=3+b](https://tex.z-dn.net/?f=%203%3D3%2Bb%20)
b =0
Substituting the values of m and b in the slope intercept form, we will get
![y= 3x](https://tex.z-dn.net/?f=%20y%3D%203x%20)
You add up 1+1+1+1+2 and you get 6. You then subtract 6 by 200 and your answer is -194