Answer: find the answer in the explanation.
Step-by-step explanation:
In the circuit A;
The moment the switch S1 is opened, bulb A, B and C will go off simultaneously because they are all connected in series.
In the circuit B;
If S1 is opened, bulb G and H will both go off automatically while other bulb will still be functioning. The reason behind this is simply because G and H are in series and both bulbs are in parallel to the other bulbs.
Bulb F will follow by going off when switch S2 is opened.
Immediately switch S3 is opened, both bulb D and E will go off simultaneously because they are in series to each other.
