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Dafna11 [192]
3 years ago
8

A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, don’

t the height.

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

The height of rectangle is 5 inches

Step-by-step explanation:

<u><em>The correct question is</em></u>

A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, Find the height

Let

x -----> the width of the rectangle in inches

y ----> the height of the rectangle in inches

d ---> diagonal measurement of the rectangle in inches

we know that

Applying the Pythagorean Theorem

d^2=x^{2}+y^{2}

we have

d=13\ in

so

13^2=x^{2}+y^{2}

169=x^{2}+y^{2} ----> equation A

x=y+7 ---> equation B

substitute equation B in equation A

169=(y+7)^{2}+y^{2}

solve for y

169=y^2+14y+49+y^{2}

2y^2+14y+49-169=0

2y^2+14y-120=0

solve the quadratic equation by graphing

using a graphing tool

The solution is y=5

see the attached figure

therefore

The height of rectangle is 5 inches

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Step 1:

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Answer:

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Step-by-step explanation:

Since we have a right angle triangle and we know two of its sides we can easily find out the thirds side (the value of d) by using the Pathagoras Theorem. In our case 7 and d are our legs and the hypotenuse is equal to 9, so...

(Based on the Pathagoras Theorem)

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Step-by-step explanation:

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What equation is equivalent to x + 8 = 21
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<span>1. Write down the probability distribution for the player earning

The player earning </span>for each event depends on the number of balls drawn subtracted the ticket price.<span>
p= 2/6
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</span>The player earnings would be: 2*1.5- $4= - $1
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This game basically a rip off.
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