The average density of Earth is 5.44 g/cm³.
<em>Mass</em>
Mass = 5.974 × 10²⁴ kg = 5.974 × 10²⁷ g
<em>Volume
</em>
<em>d</em> = 2<em>r</em> = 1.28 × 10⁴ km
<em>r</em> = 6.40 × 10³ km × (10³m/1 km) × (10² cm/1 m) = 6.40 × 10⁸ cm
<em>V</em> = ⁴/₃π<em>r</em>³ = ⁴/₃π × (6.40 × 10⁸ cm)³ = 1.098 × 10²⁷ cm³
<em>Density
</em>
Density = mass/volume = (5.974 × 10²⁷ g)/(1.098 × 10²⁷ cm³) = 5.44 g/cm³
To answer the given problem, assume that the given gases: oxygen, hydrogen, and nitrogen behave as ideal gases. The assumption is relevant so that we can make use of the partial pressure additivity of ideal gases. To determine the partial pressure exerted by nitrogen, subtract the partial pressures exerted by oxygen and hydrogen from the total pressure.
P (nitrogen) = P (total) - P (oxygen) - P (hydrogen)
P (nitrogen) = 378 kPa - 212 kPa - 101 kPa = 65 kPa
Thus, the partial pressure exerted by nitrogen is 65 kPa.
It is A. Barium
Explanation: I did that already
molaity= moles/L
molarity= 5.0 moles/ 10 L
molarity= 0.5
Answer:
I would expect to extract the acetic acid.
Explanation:
In the first step, since we are adding a concentrated acid,<u> it will react with the bases present in the mixture (diethylamine and ammonia) </u><u>forming salts</u><u>, </u><u>which are soluble in water</u>. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.
In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.