Answer:-
0.648 M
Explanation:-
Volume of Ba(OH)2= 34.63ml/1000=0.03463 litre
Number of moles of Ba(OH)2 = 0.3275 M x 0.03463 litre
= 0.01134 moles
Since Ba(OH)2 has 2 OH in its formula,
Number of moles of OH- = 2 x 0.01134=0.02268 moles.
Volume of HCl= 35ml/1000 = 0.035 litre
At the end point number of moles of H+ = number of moles of OH-.
Number of moles of HCL= Concentration of HCl x Volume of HCl
∴ Concentration of HCl = 0.02268 moles/ 0.035 litre
= 0.648 moles/ litre
= 0.648 M
Answer:

Explanation:
Hello!
In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

Thus, by plugging in the data, we obtain:

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

Best regards!
Answer:
0.47dm³
Explanation
Given parameters :
Molarity of NaCl = 6.67M
Number of moles = 3.12mol
Volume of NaCl =?
Volume of NaCl = number of moles/Molarity
Volume of NaCl = 3.12mol/6.67M
Volume of NaCl = 0.47dm³
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