Question

What mass of iron (Fe) can be obtained from 3.80 g iron (III) oxide (Fe2O3) reacting with excess carbon monoxide (CO)?

Answer 1

Answer:

2.66 g of Fe, can be obtained from the reaction

Explanation:

Let's think the reaction:

2Fe₂O₃   +  6CO  →   4Fe +  6CO₂

Ratio is 2:4, so If i have x moles of iron (III) oxide, I will produce the double of moles of Fe.

Mass / Molar mass = Mol

3.80 g / 159.7 g/m = 0.0237 moles

0.0237 moles . 2 = 0.0475 moles

Molar mass Fe = 55.85 g/m

Mol . Molar mass = Mass → 0.0475 m . 55.85 g/m = 2.66 grams