The volume of O₂ produced: 84.6 L
<h3>Further explanation</h3>
Given
7.93 mol of dinitrogen pentoxide
T = 48 + 273 = 321 K
P = 125 kPa = 1,23365 atm
Required
Volume of O₂
Solution
Decomposition reaction of dinitrogen pentoxide
2N₂O₅(g)→4NO₂(g)+O₂ (g)
From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :
= 0.5 x mol N₂O₅
= 0.5 x 7.93
= 3.965 moles
The volume of O₂ :
Answer:
Half will be green and half will be striped
Explanation:
Given green skin (G) is dominant to striped skin (g).
Cucumber 1 : Heterozygous (Gg)
Cucumber 2 : Homozygous striped (gg)
When Gg X gg :
G g
g Gg gg
g Gg gg
Half of the offspring will have Gg genotype so they will be green. Other half will have gg genotype so they will be striped.
reactions to break down glucose using oxygen to produce carbon dioxide, water and energy in the form of ATP. ... To balance the oxygen atoms for the reactant side, you need to count 6 atoms from the glucose.
Answer:
In your case, you have 8 protons and 10 electrons. This means that the atom will carry a total 2 xx (1-) = 2- net charge. Therefore, you are dealing with an anion that carries a 2- net charge, i.e. it has two more electrons than it does protons.
Answer:
P2= 125.26 Kpa
Explanation:
V1= 489.6 ml=0.4896L
V2= 750 ml= 0.750L
V1= 180 KPa= 180000 Pa
P2= ?
T1= 10 = 10 + 273.15 = 283.15K
T2= 28.7+273.15= 301.85K
180000Pa* 0.4896L/ 283.15K * 301.85K/0.75L
P2= 12526.28553
P2= 125.26 KPa
