Lewis Structure is drawn in following steps,
1) Calculate Number of Valence Electrons: # of Valence electrons in Mg = 2
# of Valence electrons in I = 7
# of Valence electrons in I = 7
---------
Total Valence electrons = 16
2) Draw Mg as a central atom surround it by two atoms of Iodine.3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.
Total Valence electrons 16
- Four electrons - 4
----------
12
4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.
The final lewis structure formed is as follow,
The correct answer is D. Using the law of conservation of mass the number of atoms on each side of the equation should be equal. Through introspection, we find that there are 2
atoms on reactant side as opposed 3Cl atoms on product side. If we add a coefficient of 3 on
we get
.
Now there are 6Cl atoms on reactant side and 2 on product side, hence we add a coefficient of 2 on both
and
. The balanced chemical equation is,

Answer:
114.7g
Explanation:
Given parameter:
Mass of Na = 45g
Unknown:
Mass of produced NaCl = ?
Solution:
The reaction equation is shown below;
2Na + Cl₂ → 2NaCl
Now, we solve from the known to the unknown. The known here is the mass of Na and it is sufficient to solve the problem;
Number of moles = 
Molar mass of Na = 23g/mol
Number of moles =
= 1.96moles
2 mole of Na produced 2 moles of NaCl
1.96 moles of Na will produce 1.96 moles of NaCl
Mass of NaCl = number of moles x molar mass
= 1.96 x [23 + 35.5]
= 114.7g