A. ratio of areas = 2^2 /5^2 = 4/25
B 14^2 : 1 = 196:1
C. ratio of perimeters would be sqrt81 = 9 times
Answer:
4 cm.
Step-by-step explanation:
Given:
A box has a volume of 308 cm cubed.
Its height is 4 cm greater than its length.
Its length is 3 cm greater than its width.
Question asked:
What is the width of the box?
<u>Solution</u>:
Let width = 
Length = 
Height = 
<u>As we know:</u>
<u />

As width can never be in negative, 
By substituting the value:-
Width =
= 4 cm
Thus, width of the box is 4 cm.
8x - 9x²y + 7y² - 2x⁴
-2x⁴ - 9x²y + 8x + 7y²
Answer:
A = 11 i believe
Step-by-step explanation: