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3 years ago

9

And archaeologist fines 30 fossils in South Dakota and Wyoming. 40% of the fossils were in South Dakota. How many fossils were f

ound in Wyoming?

1 answer:

Harrizon [31]3 years ago

3 0

Answer:

It is 12. 12 fossils were found in Wyoming.

Step-by-step explanation:

You might be interested in

Find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3). express answer in standard form

Anestetic [448]

Answer:

Final answer is $x-6y=23$

Step-by-step explanation:

We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).

So first we need to find the slope of given line.

rewirite x=6y-5 in y=mx+b form

x+5=6y

$\frac{1}{6}x+\frac{5}{6}=y$

Compare given equation with y=mx+b

we get: m=1/6

We know that parallel equations has equal slope.

Then slope of required line m=1/6

Now plug the given point (5,-3) and slope m=1/6 into point slope formula:

$y-y_1=m\left(x-x_1\right)$

$y-(-3)=\frac{1}{6}\left(x-5\right)$

$y+3=\frac{1}{6}x-\frac{5}{6}$

$y=\frac{1}{6}x-\frac{5}{6}-3$

$y=\frac{1}{6}x-\frac{23}{6}$

Now we need to rewrite that equation in standard form. Ax+By=C.

6y=x-23

x-23=6y

x-6y=23

Hence final answer is $x-6y=23$

6 0

3 years ago

There are 7 stars in each course on Mario 64. What percentage of stars

Elina [12.6K]

2 divided by 7 would give you 29%

7 0

3 years ago

Solve for a<br><br> a² + 7a - 8 = 0

masya89 [10]

Answer:

a=-8

Step-by-step explanation:

5 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago

Solve please, thank you!

djyliett [7]

Answer:

c=8

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers