Solve for a<br><br> a² + 7a

Triangles H J K and L M N are shown. The triangles have identical side lengths and angle measures. Triangle H J K is slightly lo

Hitman42 [59]

Answer:

The answer is b : translate K to N and reflect across the line containing JK

Step-by-step explanation:

I just took the quiz

4 0

3 years ago

19 A triangle has coordinate points at A 1, 3) B(3, 6) and C(3, 3). What is distance between of AC? (8 Points)

lawyer [7]

Answer:

4 I think

Step-by-step explanation:

hope this help's

3 0

3 years ago

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

3 years ago

Zaid and Matias, two farmers, constructed a 792 foot fence around their very large garden. Zaid agreed to construct 20% more of

likoan [24]

Answer:

$1.2x +x =792$

$2.2x =792$

And we got finally:

$x =\frac{792}{2.2}= 360 ft$

And the amount for Zaid would be 1.2*360 ft= 432ft

So then Zaid construc 432 ft and Matias 360 ft

Step-by-step explanation:

For this case we know that Zaid and Matias, two farmers, constructed a 792 foot fence around their very large garden so then the total is represented by 792 ft

We also know that Zaid agreed to construct 20% more of the fence than Matias did. Let's assume that the amount that construct by Matias was x then the amount constructed by Zaid would be 1.2 x representing 20% more than Matias and we can set up the following equation:

$1.2x +x =792$

$2.2x =792$

And we got finally:

$x =\frac{792}{2.2}= 360 ft$

And the amount for Zaid would be 1.2*360 ft= 432ft

So then Zaid construc 432 ft and Matias 360 ft

7 0

4 years ago

7+3x−12x=3x+17+3x−12x=3x+1 solve for X

mariarad [96]

X is equal to -11/6 or -1.8333333333..................................

4 0

3 years ago

Read 2 more answers

Solve for a a² + 7a - 8 = 0