2 years ago

Name the subset of real numbers that 55 belongs to

Mathematics

1 answer:

AleksAgata [21]2 years ago

6 0

Natural numbers or counting numbers

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Given the geometric sequence where a1 = 3 and r = √2 find a9

Zigmanuir [339]

Answer:

$a_9=48$

Step-by-step explanation:

we are given

sequence is geometric

so, we can use nth term formula

$a_n=a_1(r)^{n-1}$

we have

$a_1=3$

$r=\sqrt{2}$

we have to find a9

so, we can plug n=9

we get

$a_9=3(\sqrt{2})^{9-1}$

$a_9=2^4\cdot \:3$

$a_9=48$

8 0

2 years ago

-3q + 12 greater than equal too 4q - 30 solve for q

valentina_108 [34]

Solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Step-by-step explanation:

We need to solve the inequality: $-3q+12\geq 4q-30$ and find value of q

Solving:

$-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6$

So, solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Keywords: Solving inequality

Learn more about solving inequality at:

#learnwithBrainly

6 0

3 years ago

There are 56 trees in an apple orchard. They are arranged in equal rows. There are 8 trees in each row. How many rows of apple t

Amiraneli [1.4K]

56 ÷8=7

Hope it helped

8 0

2 years ago

Read 2 more answers

my number has 8 tens. the digital in the ones place is greater than the digit in the tens place. what my number is

Vlada [557]

Your answer to this is 89

5 0

3 years ago

Read 2 more answers

How many ways can we award a 1st, 2nd and 3rd place prize among eight contestants?

trasher [3.6K]

Answer:

Total number of ways are 336.

Step-by-step explanation:

It is required to find the number of ways in which we can award a 1st, 2nd and 3rd place prize among eight contestants. It means we need to find the number of permutations. We need to find $^8P_3$ .

Here, r = 3

So,

$^nP_r=\dfrac{n!}{(n-r)!}\\\\^8P_3=\dfrac{8!}{(8-3)!}\\\\^8P_3=\dfrac{8!}{5!}\\\\^8P_3=\dfrac{8\times 7\times 6\times 5!}{5!}\\\\^8P_3=336$

So, there are 336 ways.

6 0

2 years ago