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Sati [7]
3 years ago
6

Explain how you can use fractions strips or number lines to show that 3/4 and 6/8 are equivalent.

Mathematics
2 answers:
vivado [14]3 years ago
7 0
6/8 simplified by 2 is 3/4
timama [110]3 years ago
4 0

Answer:

answers is down there

Step-by-step explanation:

you can use fraction strips by using them 3/4 and 6/8 because they are equivalent  and that's just life :)

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I need help with #1 of this problem. It has writings on it because I just looked up the answer because I’m confused but I want t
belka [17]

In the figure below

1) Using the theorem of similar triangles (ΔBXY and ΔBAC),

\frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC}

Where

\begin{gathered} BX=4 \\ BA=5 \\ BY=6 \\ BC\text{ = x} \end{gathered}

Thus,

\begin{gathered} \frac{4}{5}=\frac{6}{x} \\ \text{cross}-\text{multiply} \\ 4\times x=6\times5 \\ 4x=30 \\ \text{divide both sides by the coefficient of x, which is 4} \\ \text{thus,} \\ \frac{4x}{4}=\frac{30}{4} \\ x=7.5 \end{gathered}

thus, BC = 7.5

2) BX = 9, BA = 15, BY = 15, YC = y

In the above diagram,

\begin{gathered} BC=BY+YC \\ \Rightarrow BC=15\text{ + y} \end{gathered}

Thus, from the theorem of similar triangles,

\begin{gathered} \frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC} \\ \frac{9}{15}=\frac{15}{15+y} \end{gathered}

solving for y, we have

\begin{gathered} \frac{9}{15}=\frac{15}{15+y} \\ \text{cross}-\text{multiply} \\ 9(15+y)=15(15) \\ \text{open brackets} \\ 135+9y=225 \\ \text{collect like terms} \\ 9y\text{ = 225}-135 \\ 9y=90 \\ \text{divide both sides by the coefficient of y, which is 9} \\ \text{thus,} \\ \frac{9y}{9}=\frac{90}{9} \\ \Rightarrow y=10 \end{gathered}

thus, YC = 10.

4 0
1 year ago
Which of the following pairs are corresponding angles?
Nat2105 [25]

Answer:2 and 7

Step-by-step explanation:

I hope it's right :)

4 0
2 years ago
Read 2 more answers
If a person tosses a coin 23 times, how many ways can he get 11 heads
EastWind [94]

Tossing a coin is a binomial experiment.

Now lets say there are 'n' repeated trials to get heads. Each of the trials can result in either a head or a tail.

All of these trials are independent since the result of one trial does not affect the result of the next trial.

Now, for 'n' repeated trials the total number of successes is given by

_{r}^{n}\textrm{C}

where 'r' denotes the number of successful results.

In our case n=23 and r=11,

Substituting the values we get,

_{11}^{23}\textrm{C}=\frac{23!}{11!\times 12!}

\frac{23!}{11!\times 12!}=1352078

Therefore, there are 1352078 ways to get heads if a person tosses a coin 23 times.


3 0
3 years ago
Algebra 2 questions
Juliette [100K]

Answer:

x = 3

Step-by-step explanation:

The fractions need to have common denominators. So, we would make the common denominator (x + 3)(x - 3), or, x^2 - 9

Multiply the numerator by the same number or variable as the denominator and then combine.

Once their is x and a number left you would solve for x.

4 0
3 years ago
If a1=7 and d=28, find a9
Mariulka [41]

Answer:

63

Step-by-step explanation:

Since a1=7 and the question is to find a9, you just have to multiply 7 and 9 which is 63

6 0
3 years ago
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