Electron volts...........
Answer
given,
expression of Kinetic energy of rotating body

ω = 34.0 rad/s
Assuming mass of the particle equal to 13 Kg
and perpendicular distance from the particle to the axis is r = 1.25 m
now,
moment of inertia of particle = ?
from the given expression
..............(1)
we know

v = r ω

putting value in equation (1)



I = 20.3125 kg.m²
Answer:
1.03m/s
Explanation:
According to the question
Fdrag = bv²
now Fdrag = weight of the box
that is Fdrag = mg
where m = mass of the box, 0.6 Kg
and g = acceleration due to gravity
thus,
Fdrag = bv² becomes
mg = bv²
making v the subject of formula


v = 1.03m/s
It's average speed during that 26 seconds was about 4.77 m/s. Without seeing the graph, we can't tell if it was going faster or slower at any particular time during that period. All we can tell is its average for the full interval.
Answer: add 10 cm plus 200 mpa divided by 2 min then caculate that into 160 bars.
Explanation: