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Finger [1]
3 years ago
13

A student at a polymer lab conducted a stress-relaxation experiment on a polymer, whose material response can be modeled by the

Maxwell model. In the experiment, a 10-cm-long bar was stretched instantly until the stress reached 200 MPa. After 2 min, the measured stress in the bar was 160 MPa. a) Calculate the relaxation time constant of the polymer. b) If the initial stress was reached by stretching the bar by 16 mm, what is the viscosity of the dashpot in the Maxwell model
Physics
1 answer:
Lorico [155]3 years ago
8 0

Answer: add 10 cm plus 200 mpa divided by 2 min then caculate that into 160 bars.

Explanation:

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The whale shark is the largest of all fish and can have the mass of three adult
ch4aika [34]

Answer:

m = 20,000 kg

Explanation:

Force, F=2.5\times 10^4\ N

Acceleration of the shark, a=1.25\ m/s^2

It is required to find the mass of the shark. Let m is the mass. Using second law of motion to find it as follows :

F = ma

Putting the value of F and a to find m

m=\dfrac{F}{a}\\\\m=\dfrac{2.5\times 10^4}{1.25}\\\\m=20,000\ kg

So, the shark's mass is 20,000 kg.

3 0
3 years ago
A ______ is a closed loop containing a source of electrical energy and a load.
gavmur [86]

Answer:

d. circuit

Explanation:

the parts of the circuit consists of a load or resistance

7 0
3 years ago
An airplane of mass 39,043.01 flies horizontally at an altitude of 9.2 km with a constant speed of 335 m/s relative to Earth. Wh
Likurg_2 [28]

Answer:

1.2 x 10¹¹ kgm²/s

Explanation:

m = mass of the airplane = 39043.01

r = altitude of the airplane = 9.2 km = 9.2 x 1000 m = 9200 m

v = speed of airplane = 335 m/s

L = Angular momentum of airplane

Angular momentum of airplane is given as

L = m v r

Inserting the values

L = (39043.01 ) (335) (9200)

L =  (39043.01 ) (3082000)

L = 1.2 x 10¹¹ kgm²/s

8 0
3 years ago
Three uniform spheres of radius 2R, R, and 3R are placed in a line, in the order given, so their centers are lined up and the sp
kolezko [41]

Answer:

x = 2.33 R from the center of mass of the smallest sphere.

Explanation:

Due to the symmetry of the spheres, the center of mass of any of them, is located just in the center of the sphere.

If we align the centers of the spheres with the x-axis, the center of mass of any of them will have only coordinates on the x-axis, so the center of  mass of the system will have coordinates on the x-axis only also.

By definition, the x-coordinate of the center of mass of a set of discrete masses m₁, m₂, m₃, can be calculated as follows:

Xcm = \frac{m1*x1+m2*x2+m3*x3}{m1+m2+3}

In this case, we need to get the coordinates of the center of mass of each sphere:

If we place the spheres in such a way that the center of the first sphere has the x-coordinate equal to its radius (so it is just touching the origin), we will have:

x₁ = 2*R

For the second sphere, the center will be located at a distance equal to the diameter of  the first sphere plus its own radius, as follows:

x₂ = 4*R + R = 5*R

Finally, for the third sphere, the center will be located at a distance equal to the diameter of  the first sphere, plus the diameter of the second sphere,  plus its own radius, as follows:

x₃ = 4*R + 2*R + 3*R = 9*R

We can calculate the mass of each sphere (assuming that all are from the same material, with a constant density), as the product of the density and the volume:

m = ρ*V

For a sphere, the volume can be calculated as follows:

\frac{4}{3} *\pi *(r)^{3}

So, we can calculate the masses of the spheres, as follows:

m₁ = ρ*\frac{4}{3} *\pi *(2r)^{3}

m₂ = ρ*\frac{4}{3} *\pi *(r)^{3}

m₃ = ρ*\frac{4}{3} *\pi *(3r)^{3}

The total mass can be calculated as follows:

M= ρ*\frac{4}{3} *\pi * (8*r³ + r³ + 27*r³) =ρ*\frac{4}{3} *\pi * 36*r³

Replacing by the values, and simplifying common terms, we can calculate the x-coordinate of the center of mass of the system as follows:

Xcm = \frac{m1*x1+m2*x2+m3*x3}{m1+m2+3}

Xcm = \frac{(8*R^{3} *2*R)+(R^{3}*(5*R))+27*R^{3}*(9*R))}{36*R^{3} }=\frac{264*R^{4} x}{36*R^{3}} = 7.33 R

As the x-coordinate of the center fof mass of the entire system is located at 7.33*R from the origin, and the center of mass of the smallest sphere is located at 5*R from the origin, the center of mass of the system is located at a distance d:

d = 7.33*R - 5*R = 2.33 R

4 0
3 years ago
A 10-kg object is pushed across a rough surface. It begins at rest and accelerates to a speed of 4 m/s in a distance of 5m. Whic
brilliants [131]

Answer:

Explanation:

Unbalanced Force according to newton's second law is the one which causes  the object to move or break its state of rest on application of force.

Here the object accelerate to a speed of 4 m/s and moves a distance of 5 m on application of force .

Thus we can say that the applied force is unbalanced in nature.

5 0
3 years ago
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