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ratelena [41]
2 years ago
13

Please help thank you

Physics
1 answer:
Margarita [4]2 years ago
7 0

Answer:

\theta \approx 59.036^{\circ}, T_{2} \approx 23.324\,N

Explanation:

First we build the Free Body Diagram (please see first image for further details) associated with the mass, we notice that system consist of a three forces that form a right triangle (please see second image for further details): (i) The weight of the mass, (ii) two tensions.

The requested tension and angle can be found by the following trigonometrical and geometrical expressions:

\theta = \tan^{-1} \frac{W}{T_{2}} (1)

T_{1} = \sqrt{W^{2}+T_{2}^{2}} (2)

Where:

W - Weight of the mass, measured in newtons.

T_{1}, T_{2} - Tensions from the mass, measured in newtons.

If we know that W = 20\,N and T_{2} = 12\,N, then the requested values are, respectively:

\theta = \tan^{-1} \frac{20\,N}{12\,N}

\theta \approx 59.036^{\circ}

T_{2} = \sqrt{(20\,N)^{2}+(12\,N)^{2}}

T_{2} \approx 23.324\,N

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