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aliina [53]
2 years ago
5

A spring has a length of 0.270 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a 2.80 kg mass hangs from it.

(a) What is the force constant (in N/m) of the spring?
Physics
1 answer:
kati45 [8]2 years ago
3 0

Answer:

k  = 51.09 N/m

Explanation:

Given,

mass, m₁ = 0.3 Kg

length of spring, x₁ = 0.27 m

Mass, m₂ = 2.80 Kg

Length of spring, x₂ = 0.750

We know that

Restoring force, F = k x

Gravitation force, F = m g

Now,

m₁ g = k x₁ ......(1)

And

m₂ g = k x₂   .......(2)

where k is spring constant

Subtracting equation (2)- (1)

(m₂-m₁)g = k(x₂-x₁)

(2.8-0.3) x 9.81 = k (0.75 - 0.27)

24.525 = k x 0.48

k  = 51.09 N/m

Hence, spring constant is 51.09 N/m.

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Unpolarized light is incident upon two ideal polarizing filters that do not have their transmission axes aligned. If 19% of the
Zepler [3.9K]

Answer:

51.94°

Explanation:

I_0 = Unpolarized light

I_2 = Light after passing though second filter = 0.19I_0

Polarized light passing through first filter

I_1=\frac{I_0}{2}

Polarized light passing through second filter

I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow 0.19I_0=\frac{I_0}{2}cos^2\theta\\\Rightarrow cos^2\theta=\frac{0.19I_0}{\frac{I_0}{2}}\\\Rightarrow cos\theta=\sqrt{\frac{0.19I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{\frac{0.19I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{0.19\times 2}\\\Rightarrow \theta=cos^{-1}\sqrt{0.38}\\\Rightarrow \theta=51.94^{\circ}

The angle between the two filters is 51.94°

5 0
2 years ago
What would be the result of an alpha particle coming into a magnetic field?
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A 250 kg cart is at the top of a hill that is 32 m high, what is its potential energy?
atroni [7]

Answer:

<h2>80,000 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

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From the question we have

PE = 250 × 10 × 32

We have the final answer as

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Answer:

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W = weight of the object

m = mass of the object

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