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Gnom [1K]
3 years ago
14

What is one thing that you learned in math in this past year that you were proud to have accomplished? Take a few sentences to t

ell me about it.
Mathematics
2 answers:
babymother [125]3 years ago
6 0

Answer:

absolutely nothing

Step-by-step explanation:

lol im joking but i have learned how to use a bar model and how to use a x and y axis

Flauer [41]3 years ago
5 0

Answer:

Well, I think my best accomplishment was being able to pass Algebra, I don't think I would be where I am had I not had the best teacher in the world, and honestly I thank her so much for having the patients to deal with me, an anxiety filled ADHD, hyper teen  

Step-by-step explanation:

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Can someone tell me what this figure is HEEEEEEEEEELP !!!!!!!<br><br>​
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

its a variable. this one represents x. a variable is something that represents an unknown value.

8 0
3 years ago
Read 2 more answers
Rewrite in simplest terms: 2(-4p-6)-5p2(−4p−6)−5p
irina1246 [14]

Answer: 20p³+30p²-13p-12

Step-by-step explanation:

2(-4p-6)-5p²(-4p-6)-5p

-8p-12+20p³+30p²-5p

20p³+30p²-13p-12

please click thanks and mark brainliest if you like :)

3 0
3 years ago
Read 2 more answers
Solve for x<br> -30=5(x+1)
mariarad [96]

Answer:

-5=x

Step-by-step explanation:

-30=5x+5

-25=5x

-5=x

5 0
3 years ago
Read 2 more answers
Please help need it asap
Studentka2010 [4]

Answer:

195

Step-by-step explanation:

87+38+40=165

360-165=195

Hope this helps!

If not, I am sorry.

4 0
1 year ago
Two friends argue about the calculated probability of flipping a coin to show heads three times in a row. steve mentions that ea
den301095 [7]

Solution:

A coin is flipped three times,resulting three heads in a row.

Since Steve has mentioned that ,  each flip  of a coin is unconnected to the previous flip.

Two or more events are said to be independent if occurrence of one of them is not affected by the Occurrence of other.

This is an example of independent events.

In terms of probability, P (A∩B∩C)= P(A)×P(B)×P(C)

4 0
3 years ago
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