Answer:
z = 21 ; y= 16
Step-by-step explanation:
first of all we have to isolate a variable.
In second expression we can obtain:
3y = 2z+6
y = 2/3 z + 2
now we have to substitute this value in the first equation and solve it
8(2/3z+2)-5z = 23
16/3z + 16 -5z = 23
16z +48 - 15z = 69
z = 21
now we have to substitute z in the second equation:
y = 2/3 (21) +2
y = 14+ 2 = 16
y = 16
This response is based upon your having had some background in calculus. "dx" is not introduced before that.
Take a look at the sample function y = f(x) = x^2 + 9. Here x is the independent variable; the dependent variable y changes with x.
Now, for a big jump: we consider finding the area under a curve (graph) between x = a and x = b. We subdivide that interval [a,b] into n vertical slices of area. Each of those slices has its own area: f(x)*dx, where dx represents the width of such subarea. f(x)*dx is the actual subarea. To find the total area under the curve f(x) between x= a and x = b, we add up all of these individual subareas between x = a and x = b. Note that the subinterval width is
b-a
dx = ---------- , and that dx becomes smaller and smaller as the number of
n subintervals increases.
Once again, this all makes sense only if you've begun calculus (particularly integral calculus). Do not try to relate it to earlier math courses.
I have no idea I’m doing the same thing rn but good luck bro bro
Answer:
8
Step-by-step explanation:
I've taken test
