What is f(x)=-3(x+1)(x+1) in standard form

Mathematics

1 answer:

expeople1 [14]2 years ago

3 0

Answer:

f(x) = 3x² + 6x + 3

Step-by-step explanation:

The standard form of a quadratic is $ax^2 + bx + c$ . To write the equation f(x)=-3(x+1)(x+1) in standard form, multiply the factors using the distributive property and combining like terms.

f(x)=-3(x+1)(x+1)

f(x) = 3(x²+x+x+1)

f(x) = 3x² + 3x + 3x + 3

f(x) = 3x² + 6x + 3

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