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Arturiano [62]
2 years ago
11

What is f(x)=-3(x+1)(x+1) in standard form

Mathematics
1 answer:
expeople1 [14]2 years ago
3 0

Answer:

f(x) = 3x² + 6x + 3

Step-by-step explanation:

The standard form of a quadratic is ax^2 + bx + c. To write the equation f(x)=-3(x+1)(x+1)  in standard form, multiply the factors using the distributive property and combining like terms.

f(x)=-3(x+1)(x+1)

f(x) = 3(x²+x+x+1)

f(x) = 3x² + 3x + 3x + 3

f(x) = 3x² + 6x + 3

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Answer:

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Step-by-step explanation:

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P(X=x)=\frac{e^{-\lambda t}({-\lambda t})^x}{x!}  for x=0,1,2...

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