All categories

3 years ago

Which of the following is closest to the value of x?

Mathematics

2 answers:

valina [46]3 years ago

5 0

By the Pythagorean theorem:

AC = √(AB²-BC²) = √(9²-4²) = √(81-16) = √65 ≈ 8
CD = √(BD²-BC²) = √(5²-4²) = √(25-16) = √9 = 3
x = AC - CD = 8 - 3 = 5

Answer: 5

avanturin [10]3 years ago

3 0

Hello, the closest to x is 6

You might be interested in

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

Jobisdone [24]

Answer:

$f(x)=x^4-9x^2-50x-150$

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is $f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))$

We expand to get: $f(x)=(x^2-2x-15)(x^2+2x+10)$

We expand further to get:\

$f(x)=x^4-9x^2-50x-150$

3 0

3 years ago

Which is a possible turning point for the continuous<br> function f(x)?<br> HELP ASAP

maxonik [38]

Answer: B. (-2, -1)

Step-by-step explanation:

(-2, -1) has a y-coordinate (-1) closer to 0 than the rest of the y-coordinates. And 0 would be turning point in this equation.

7 0

3 years ago

Read 2 more answers

Help me out please and thank you

faust18 [17]

<h3>Answer: 1</h3>

========================================================

Explanation:

We're given the height in relation to base BC, so we need to find the length of this base. This is the same as finding the distance from B to C.

Turn to the distance formula

$d = \text{Distance from B to C}\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y^2)^2}\\\\d = \sqrt{(-2-(-3))^2+(-1-(-2))^2}\\\\d = \sqrt{(-2+3)^2+(-1+2)^2}\\\\d = \sqrt{(1)^2+(1)^2}\\\\d = \sqrt{1+1}\\\\d = \sqrt{2}\\\\$

Coincidentally, the base and height are the same. This won't always be the case.

Now we can find the area of the triangle

$A = \text{Area of triangle}\\\\A = \frac{1}{2}*\text{Base}*\text{Height}\\\\A = \frac{1}{2}*\sqrt{2}*\sqrt{2}\\\\A = \frac{1}{2}*\sqrt{2*2}\\\\A = \frac{1}{2}*\sqrt{4}\\\\A = \frac{1}{2}*2\\\\A = 1\\\\$

The area of the triangle is 1 square unit.

See diagram below.

5 0

3 years ago

You are choosing between two different cell phone plans. The first plan charges a rate of 23 cents per minute. The second plan c

jenyasd209 [6]

Answer:

357 minutes

Step-by-step explanation:

I subtracted 9 cents/minute from the 23 cents/minute to get 14 cents to get the difference between the two per minute charges. I then divided the monthly cost of $49.95 by .14 to get 356.79... So if you used 357 minutes in a month, the second plan would be 3 cents cheaper at $82.08 (.09 x 357= 32.13 + 49.95), vs. the first plan costing $82.11 (.23 x 357). At 356 minutes the first plan would still be cheaper.

3 0

3 years ago

What is the missing step in the given proof?

Anon25 [30]

<span>Statement: ∠7 and ∠8 are supplementary.
Reason: Linear Pair Theorem</span>

8 0

3 years ago

Read 2 more answers