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pshichka [43]
3 years ago
10

The apparent magnitude of a star is the brightness of a star

Computers and Technology
2 answers:
mihalych1998 [28]3 years ago
8 0

Answer:

c. as seen from the Earth without the effect of the atmosphere

Explanation:

The stars and objects in the sky emit light that, regardless of the distance they are, reaches us with greater or less intensity, being brighter the closer, larger, and / or higher temperature they have, and vice versa. This luminosity is called magnitude, and it is known that since ancient civilizations it was classified by the intensity of its brightness.

The apparent magnitude is the luminosity that the object shows us as it is seen in the sky, regardless of the temperature, the size or the distance at which it is located, and it is expressed with a number that can result, depending on the brightness , positive or negative, being brighter the smaller that number is (an object with a negative magnitude will always be brighter than one with a positive magnitude).

We can verify that, as we said at the beginning of the entry, today we observe magnitudes that are far from the first to the sixth used by Hipparchus for its catalog. Later we will see what is being talked about here with some examples, although the fact that there are magnitudes with a negative value should already give you a clue as to what you will see.

Lana71 [14]3 years ago
6 0
<span>c. as seen from the Earth without the effect of the atmosphere</span>
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What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

7 0
3 years ago
Discuss Hardware is useless without software?​
Alexus [3.1K]

Explanation:

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3 years ago
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dusya [7]

Answer:

when user wants duplicate copy of the object

Explanation:

Encapsulation are one of the key foundations of object-oriented programming (OOP). It involves the bundling of data or information with the methods and various techniques which operate on that data.

It can be used in hiding the true values or state of a structured data object that is in a class, preventing unauthorized parties' direct access to them.

The circumstances that can be allowed in returning a reference to the existing Engine is when user wants duplicate copy of the object.

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3 years ago
Christina used the following expression to calculate the average ages of her three program users: average = age1 + age2 + age3 /
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I am thinking it's A. Not so sure though.
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