The hypotenuse can be solved by this formula. X^2 = 6^2 +6^2
X^2=64
Usually you cut it down to 8 but it wants the squared form so 64.
179 students in 3rd grade, 189 4th graders, and 209 5th graders. 577 students total!
Answer:
B. is exactly 1 triangle
Step-by-step explanation:
For any given triangle, the sum of the internal angles is
. Thus from the given question, adding the given angles;
30° + 70° + 80° = 
Therefore, only one triangle can be produced with the given measure of angles. This implies that there is exactly one triangle. So that the correct option is B.
Answer:
(f + g)(x) = 5x - 3
Step-by-step explanation:
(f + g)(x)
= f(x) + g(x)
= 2x + 4 + 3x - 7 ← collect like terms
= 5x - 3
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN