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Maslowich
3 years ago
9

Simplify 8/9-5/12 in simplest form

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0

Let's first put 8/9 and 5/12 in simplest form.

We need to have the denominators at the same value by find the greatest common multiple.

The GCM of 9 and 12 is 36. By making both denominators 36, we also have to change the numerator.

36/9 is 4 so the numerator of 8/9 has to be multiplied by 4, making that 32/36.

36/12 is 3 so the numerator of 5/12 has to be multiplied by 3, making that 15/36.

Now, that we have the same denominators, we can subtract.

32/36-15/36 can be done simply by just subtracting the numerators together. Remember, the denominators stay the same.

32/35-15/36 = 17/36

Since there is no least common multiple of 17 and 36, then 17/36 is the final answer.

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Two shops, Lidal and Oldi, sell the same brand of toilet rolls but with different package sizes.
xeze [42]

Lidal's price is better

Step-by-step explanation:

Lidal

4 for £2.04

1 for £2.04/4= £0.51= 51 p

Oldi

9 for £4.68

1 for £4.68/9= £0.52= 51 p

Lidal offers better price per roll

5 0
3 years ago
in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)
Nimfa-mama [501]

Answer:

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

Step-by-step explanation:

Let \vec u and \vec a, from Linear Algebra we get that component of \vec u parallel to \vec a by using this formula:

\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a (Eq. 1)

Where \|\vec a\| is the norm of \vec a, which is equal to \|\vec a\| = \sqrt{\vec a\bullet \vec a}. (Eq. 2)

If we know that \vec u =(2,1,1,2) and \vec a=(4,-4,2,-2), then we get that vector component of \vec u parallel to \vec a is:

\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)

Lastly, we find the vector component of \vec u orthogonal to \vec a by applying this vector sum identity:

\vec  u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a} (Eq. 3)

If we get that \vec u =(2,1,1,2) and \vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right), the vector component of \vec u is:

\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10}    \right)

\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

4 0
3 years ago
What’s the answer to this problem that I can not figure out
Maslowich

Answer:

-64/3 HOPE THIS HELPS if you need more help let me know

4 0
3 years ago
Another brainliest help again
UkoKoshka [18]

Answer:

Im pretty sure it is 2,4, and 5

Step-by-step explanation:

3 0
3 years ago
A survey of a group of tourists was taken in St. Louis. The survey showed the​ following: of the tourists plan to visit Gateway​
kykrilka [37]

Answer:

14 people visited art museum.

Step-by-step explanation:

A Group of 115 tourists took in St. Louis.

61 tourists plan to visit the Gateway,

48 plan to visit the zoo,

11 plan to visit the Art Museum  but not the Gateway arch,

12 plan to visit the Art Museum, but not the zoo,

17 plan to visit the Gateway arch and zoo but not the art museum,

Seven plan to visit the art museum, the zoo and gateway arch,

Sixteen plan to visit none of three places.

How many plans to visit the art museum?

Let

Number of tourists plan to visit Art museum = x

People plan to visit none of three places = 16 = 115 – 16 = 99

People who visited gateway arch = 61 - 12 - 17 -7=  25

People who visited zoo = 48 – 11 – 17 – 7 = 13

People who visited art museum = 99 – 11 – 17- 7 – 25 – 13 = 14

14 people visited art museum.

3 0
3 years ago
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