we have the number
![6-\sqrt[]{-40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B-40%7D)
Remember that
i^2=-1
so
substitute
![6-\sqrt[]{(i^2)40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B%28i%5E2%2940%7D)
![6-2i\sqrt[]{10}](https://tex.z-dn.net/?f=6-2i%5Csqrt%5B%5D%7B10%7D)
therefore
the real part is 6
the imaginary part is -2√10
B -2x8y18
Use photo math it’s helpful
Answer:
2
Step-by-step explanation:
Since the 3's are the same on either side, you need to find a number that, when multiplied by 9, yields 18. The only number that satisfies that is 2, which is the answer. Hope this helps!
Your equation would be 2x - 12 + 3x - 15 = 23
Combine like terms and solve for x