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Law Incorporation [45]
3 years ago
11

Simplify the ratio 36 to 45.

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0
The ratio is 4/5. They both can be reduced down by 9.

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eduard

the 1st ne is 5x - 7 = 8

x= 3

the last im not sure

6 0
4 years ago
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What is the solution to the system of linear equations y-x=4 and y+2x=1?
Maksim231197 [3]
 -x + y = 4
2x + y = 1
     -3x = 3
      -3    -3
        x = -1
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4 0
3 years ago
A cylindrical tank holds about 615.44
djyliett [7]

Answer:

The height is 15.992 in

Step-by-step explanation:

1. The equation for a cylinder is V=\pi r^2h.  In this case, the equation looks like 615.44=\pi (3.5)^2h

2. Isolate h by dividing both sides of the equation by \pi (3.5)^2

3. This leaves us with \frac{615.44}{\pi (3.5)^2}=h

4. Solve for the left side, which leaves us with h = 15.992 (rounded to the nearest thousandth)

4 0
2 years ago
Which fraction shows 3.4 as a quotient of two integers?<br><br> 19/5<br> 17/5<br> 15/4<br> 13/10
Vilka [71]
The answer is B. \frac{17}{5}
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8 0
3 years ago
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THIS IS ALGEBRA 2 CAN ANYONE SOLVE IT FOR ME?
Katen [24]

Answer:

(a)  128 ft

(b)  4 s

(c)  Vertex:  (1, 144)

Step-by-step explanation:

Given information:

  • h(t) = height in feet
  • t = time in seconds after the launch

<h3><u>Part (a)</u></h3>

The height of the projectile at launch is the value of h(t) when t = 0 (the y-intercept).

Therefore, from inspection of the graph, the y-intercept is (0, 128).

So the <u>height of the projectile at launch is 128 ft</u>.

<h3><u>Part (b)</u></h3>

The length of time it took for the projectile to land is the time from the beginning (when t = 0) to when the height is 0 (the x-intercept).  

From inspection of the graph, the x-intercept is (4, 0)

So the <u>length of time it took for the projectile to land is 4 s</u>.

<h3><u>Part (c)</u></h3>

The vertex is the turning point (minimum/maximum point).

Therefore, from inspection of the graph, the <u>vertex is (1, 144)</u>.

The vertex represents the time and height at which the projectile was at its maximum.  So at the time of 1 second, the projectile was at its maximum height of 144 ft.

7 0
2 years ago
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