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iragen [17]
3 years ago
11

Clover the Clown charges $49.50 for a private party event and $55.25 for a community event. He did 4 private party events and 3

community events each week for 5 weeks.
How much money did Clover the Clown earn altogether?
Mathematics
1 answer:
goldenfox [79]3 years ago
6 0
$49.50 x 4 = 198
$55.25 x 3 = $165.75
All together it must be 1,818.75
Hopefully this was right
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The probability of getting a 4 is 1/6 and the probability of getting an even number is 3/6. So u multiply your two fractions so the answer is 3/36 which simplifies to 1/12. The
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Help.tttttttttlloppp<br>​
DochEvi [55]

Answer:

I think it is   20.75°

Step-by-step explanation:

An interesting problem!

the m arcVYX = 282°         so the m arcVYXV must equal 360°

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I beleive m angle UVX - m arcVX = 78°

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20.75° = x      

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3 years ago
A school newspaper decides to survey all the students enrolled in a gym class to determine the percentage of these students who
pishuonlain [190]

Answer:

A sudents who take gym class

Step-by-step explanation:

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3 0
3 years ago
The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t
damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that \mu = 3

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498

P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494

P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240

P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472

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3 0
2 years ago
Plssssss help fast!!!!Launching From a Tower
aleksandrvk [35]

Answer:

A. h = 64

B.  t = 4 -> 4 seconds

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D. maximum height is 100 ft

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

Step-by-step explanation:

h = -16t2 + vt + 64

A. What tower platform height was the projectile launched from?

when the projectile was not launched, t = 0

h = -16(0)^2 + v(0) + 64 = 64

B. How long was the projectile in the air?

if the projectile lands, its height = 0 so substitute 0 for h

0 = -16(t)^2 + 48(t) + 64

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 = -16(t - 4)(t + 1)

t = 4 or t = -1

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C. When did it reach its maximum height?

maximum -> t=-b/2a where in -16(t)^2 + 48(t) + 64, b = 48 and a = -16

t = -48/-32 = 1.5

D. What was its maximum height?

plug t = 1.5 into -16(t)^2 + 48(t) + 64

-16(1.5)^2 + 48(1.5) + 64 = -36 + 72 + 64 = 100

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

6 0
2 years ago
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