A triangle has side lengths of 6, 8, and 5. Is it a right, acute or obtuse triangle

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

2 years ago

At a large university, the probability that a student takes calculus and is on the dean's list is 0.042. the probability that th

cestrela7 [59]

As this is probability, we can use the next formulas and tell how is this going to be:
P(A) = student on the dean's list
P(B) = student taking calculus 
P(A n B) = 0.042 
P(A) = 0.21 
So, P(B) = 0.042/0.21 
= 0.2
So the probability here is of 0.2

4 0

3 years ago

john is looking at a map with a scale of 1/4 inch=20 miles. he measured the distance from his home to the bowling alley in town

Sergio039 [100]

1 inch=80mi

2.5*80mi=200 mi

5 0

3 years ago

You have two exponential functions. One function has the formula g(x) = 5 ^x . The other function has the formula h(x) = 5^-x .

Shkiper50 [21]

We are given with two functions here: h(x) is 5^-x and g(x) is 5^x . we are asked in the problem to determine the value of the expression (g-h)(x). In this case, we just have to employ subtraction to the given functions. That is

(g-h)(x) = 5^x - 5^-x
= 5^x -1/5^x
= (5^2x -1)/5^x

4 0

3 years ago

Read 2 more answers

WHats 100000000000000 x 1000000000000000000000

ser-zykov [4K]

Answer:

1e+35

Step-by-step explanation:

7 0

3 years ago