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3 years ago

HELP PICTURE IS SHOWN

Mathematics

2 answers:

Flauer [41]3 years ago

8 0

I'm pretty sure it's false

Kaylis [27]3 years ago

4 0

I would say false, but i dont want your answer to be wrong... Im sorry!

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In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz

Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a $\frac{1}{4} = 0.25$ probability of getting ir right. So $\pi = 0.25$ . There are five questions, so $n = 5$ .

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

$P = 0.75(0.25) = 0.1875$

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: $P = P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955$

$P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637$

$P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592$

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

$P = P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879$

$P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146$

$P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001$

$P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035$

There is a 10.35% probability that she gets the majority of the questions right.

6 0

3 years ago

PLEASE HELP Graph 4x + y = 6x - 1 Show your work AND explain the method used to determine the graph

Anna007 [38]

Answer:

y=2x-1

Step-by-step explanation:

y= 6x-1-4x

y=2x-1

3 0

4 years ago

Is eliana right or wrong? Explain please! Brainliest for right answer

likoan [24]

She is wrong she should have added 18 to both sides

7 0

3 years ago

Sam chose one marble from a bag containing 2 red marbles, 3 white marbles, and 10 black marbles. Find the probability that the m

Anvisha [2.4K]

Answer:

P(black) = 2/3

Step-by-step explanation:

We need to find the total number of marbles

2 red marbles+ 3 white marbles+ 10 black marbles = 15 marbles

To find the probability that Sam chose a black marble, we take the number of black marbles and divide by the total number of marbles

P(black) = black marbles/total marbles

= 10/15

Divide the top and bottom by 5

= 2/3

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3 years ago

Which expression is not a polynomial?

Nezavi [6.7K]

Answer:

Step-by-step explanation:

A term in a polynomial is a single number or a number multiplied by any number of variables. A polynomial is a sum of terms.

The only thing that can be done with variables in a polynomial is to multiply them by numbers or other variables. In a polynomial, you cannot: divide by a variable (have a variable in a denominator), have a root of a variable, have a log of a variable, have a variable as an exponent, etc.

All expressions are polynomials except for D. In D., the negative exponents mean division by variables.

7 0

3 years ago