130 revolutions is 130×85π=34714.60cm=347.146m or 347m to the nearest metre.
Answer:
0.54
Step-by-step explanation:
You take 54 and divide it by 100
54/100 =0.54
Hope this helps!!
$469.
376/4 = 94.
Then add that too 346
94 + 346 = 469
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
-2
Step-by-step explanation:
First you should write out the entire word equation into one you may recongnize:
7x - 12 = -3x - 32
After this, solve for x:
7x + 3x = 12 - 32
<u>10x</u> = <u>-20</u>
10 10
x = -2
the number is -2
