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Katyanochek1 [597]
3 years ago
11

In a four digit number, the digit in thousand’s place in 4 and the digit in the one’s place is twice that in the thousand’s plac

e. The number has no hundreds. The ten’s place digit is the difference between the digit in the thousand’s place and the hundred’s place. Find the number.
Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

Step-by-step explanation:

As 4 is accumulated by thousands place

And ones place is 4 into 2/twice

And hundreds place accumulates zero

And tens place is 4 - 0=4

The no is

4048

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The graph of a quadratic equation passes through
Katarina [22]

Answer:

2

Step-by-step explanation:

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2 years ago
Point C ∈ AB , AB = 30m. Point C is 1.5 times farther from point A than from point B. Find AC and CB.
Shtirlitz [24]

let's say that C is "x" units farther from B, that means that CB = x, and therefore AC = 1.5x.


\bf \underset{\leftarrow ~~30~~\to}{\boxed{A}\stackrel{1.5x}{\rule[0.35em]{18em}{0.25pt}}C\stackrel{x}{\rule[0.35em]{10em}{0.25pt}}\boxed{B}}
\\\\\\
AB=AC+CB\implies \stackrel{AB}{30}=\stackrel{AC}{1.5x}+\stackrel{CB}{x}\implies 30=2.5x
\\\\\\
\cfrac{30}{2.5}=x\implies 12=x
\\\\[-0.35em]
~\dotfill\\\\
AC=1.5(12)\implies AC=18~\hspace{8em} CB=x\implies CB=12

8 0
3 years ago
Does anyone know this ?? i’m super confused :(
LuckyWell [14K]
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8 0
3 years ago
Please help me find the difference and tell me what to type, i will mark brainliest
frez [133]

Answer:

g^3 - 7

Step-by-step explanation:

write

(2g^2+3g-8)-(5g+1)

(5g^3-8)-(5g+1)

and then you get g^3 - 7

sorry if it is not write but it should be

4 0
3 years ago
USA Today reports that about 25% of all prison parolees become repeat offenders. Alice is a social worker whose job is to counse
pychu [463]

Answer:

a) P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039  

P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469  

P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211  

P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422  

P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316

b) E(X) = np = 4*0.75=3

c) Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866

d) P(X \geq 3) \geq 0.98

And the dsitribution that satisfy this is X\sim Binom(n=9,p=0.75

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=4, p=1-0.25=0.75)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039  

P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469  

P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211  

P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422  

P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316

Part b

The expected value is givn by:

E(X) = np = 4*0.75=3

Part c

For the standard deviation we have this:

Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866

Part d

For this case the sample size needs to be higher or equal to 9. Since we need a value such that:

P(X \geq 3) \geq 0.98

And the dsitribution that satisfy this is X\sim Binom(n=9,p=0.75

We can verify this using the following code:

"=1-BINOM.DIST(3,9,0.75,TRUE)" and we got 0.99 and the condition is satisfied.

4 0
3 years ago
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