Explanation:
In Hardy-Weinberg equilibrium...
p represents the dominant allele frequency
q represents the frequency of the recessive allele
q^2 = the genotypic frequency of the homozygous recessive
p^2= the genotypic frequency of the homozygous dominant
2pq= the frequency of the heterozygous genotype
Further Explanation:
Sequences of DNA make up genes which can have different forms called alleles. DNA, which makes up the genotype, is transcribed into mRNA and later translated into amino acids which are linked together by rRNA to form proteins which make up the phenotype of an organism. Mutations in DNA sequences form new alleles, and affect the corresponding mRNA and thus the protein encoded. Along with genetic drift, selective mating and natural selection, evolution may occur within populations.
Some alleles become fixed within a population over time. In Hardy-Weinberg equilibrium for a specific gene that is not undergoing evolution- allelic frequencies are stable over several generations. During this period, mutations do not occur within the population.
Learn more about mutations at brainly.com/question/4602376
Learn more about DNA and RNA at brainly.com/question/2416343?source=aid8411316
#LearnWithBrainly
Answer:
The correct answer is a. Pseudomonas aeruginosa would be colorless on EMB
Explanation:
Pseudomonas aeruginosa is a gram-positive bacteria that is rod shape. It shows a few nutritional requirements and can even adapt to those conditions in which the other bacteria can be adapt.
It is non-fermentative bacteria so it does not ferment lactose and other carbohydrates. As EMB agar contains lactose and some dye, therefore, the lactose fermenting bacteria ferment the lactose and show good growth and color change.
But as Pseudomonas aeruginosa is a non-fermentative bacteria it does not ferment lactose and does not show any color and forms a colorless colony. Therefore the correct answer is a.