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Ivan
3 years ago
6

Please Help! It is Pre-Calc and I need to know the answer!

Mathematics
2 answers:
slava [35]3 years ago
7 0

That's the derivative at x=9 so will be 4(9³)=2916.  Let's do it the hard way.

f(x) = x⁴

f(9)=9⁴

f(9+h)=(9+h)⁴ = 9⁴ +4·9³ h +  6·9²h² + 36h³ + h⁴

(f(9+h)-f(9))/h = 4·9³  +  6·9²h + 4·9h² + h³

\lim_{h\to 0} (f(x+h)-f(x))/h =4\cdot 9^3 = 2916

Answer: Choice C, 2916

alexandr402 [8]3 years ago
5 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans  so 100 - 60 = 40 are democrats).

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Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}

Now compute each combination separately:

\large \binom{6}{4}=\frac{6!}{4!2!}=15\\\\\binom{50}{2}=\frac{50!}{2!48!}=1225\\\\\binom{50}{6}=\frac{50!}{6!44!}=15890700

and now replace the values:

\large \frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}=\frac{15*1225}{15890700}=\frac{18375}{15890700}=\frac{5}{4324}

and that is it.

If the decimal expression is preferred then divide the fractions to get 0.001156337

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3 years ago
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