I'm guessing the series is supposed to be

By the ratio test, the series converges if the following limit is less than 1.

The first
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terms in the numerator's denominator cancel with the denominator's denominator:
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
also cancels out and the remaining factor of

can be pulled out of the limit (as it doesn't depend on
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).

which means the series converges everywhere (independently of

), and so the radius of convergence is infinite.
Your answer is A.) for ur problem
<span>The mean of a set of data is 148.87 and its standard deviation is 68.29. Find the z score for a value of 490.19
the z-score is given by:
z=(x-</span>μ<span>)/</span>σ
plugging in the values in the expression we get:
z=(490.19-149.87)/68.29
z=340.32/68.29
z=4.9835
Answer:
21
Step-by-step explanation:
the pattern is plus 6
13. you need a total of 14 a week and you have 1