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Morgarella [4.7K]
3 years ago
5

Simplify the algebraic expression -2(x - 3) + 4(-2x + 8)

Mathematics
1 answer:
dangina [55]3 years ago
7 0
The answer to this equation is :-10x+38 because
-2x(x-3)+4(-2x+8)
(-2x+6)+(-8x+32)
(-2x+6)(-8x+32)
-2x+6-8x+32
-10x+38
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Answer:

(12, 40)

Step-by-step explanation:

The first thing is to assume that we have a point with the following coordinates (x, y).

Now, we can have two different cases since the meaning of the expansion of a point is moving to a new point that is a greater distance from the origin if we are expanding by a value, that is, an integer in the system of coordinates and the other case is that if we are dilating by a fraction that is between 0 <x <1, then the distance from the origin decreases.

Now, the point (x, y) goes through an expansion by a scale factor f (with the origin as the expansion point), then the new coordinate of the point = [f * x, f * y], that scale factor has the value of 3, so if we replace we have:

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Step-by-step explanation:

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A police cruiser is traveling at 20.0 m/s when the officer spies a speeder. The cruiser accelerates at 3.0 m/s^2 for 5.0 seconds
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For the first 5.0 seconds, the cruiser covers a distance of

\left(20.0\dfrac{\rm m}{\rm s}\right)(5.0\,\mathrm s)+\dfrac12\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)^2=137.5\,\mathrm m

At this point, the cruiser will have achieved a velocity of

\left(20.0\dfrac{\rm m}{\rm s}\right)+\left(3.0\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)=35\dfrac{\rm m}{\rm s}

The cruiser will take

\left(35\dfrac{\rm m}{\rm s}\right)-\left(5.0\dfrac{\rm m}{\mathrm s^2}\right)t=0\implies t=7.0\,\mathrm s

to come to a stop as it decelerates. It will have covered a total distance of

(137.5\,\mathrm m)+\left(35\dfrac{\rm m}{\rm s}\right)(7.0\,\mathrm s)+\dfrac12\left(-5.0\dfrac{\rm m}{\mathrm s^2}\right)(7.0\,\mathrm s)^2=\boxed{260\,\mathrm m}

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20x 5 i hope this helps you!

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