The given temperatures of 70 °F, 50 °F, and 35 °F, at the given 3, 3, and
6 days give the following step function;
- Please find attached the graph of the step function?
<h3>How can the step function be written?</h3>
The temperature at it is fermented in the first three days = 70 °F
From day 3 to 6 the temperature = 50 °F
From day 6 to day 12, the temperature at which it is kept in the freezer = 35 °F
The step function is therefore;
The graph of the above function created with MS Excel is attached
Learn more about step functions here:
brainly.com/question/2509505
Answer: s = 7
Step-by-step explanation:
27 is simply 9 times 3.
Thus, simply do 63/9 to get 7.
Hope it helps :)
Let's solve the inequality. Subtract 5 from both sides. The result will be
<span>x ≥ 5. This states, "x is equal to or greater than 5."
</span>
Plot 5 on the number line, using a dark solid dot. Then draw an arrow from that point to the right.
Answer:
10. First you multiply both sides by 3, making it 2x + 5 = 24
Then you subtract 5 from both sides making it 2x = 19
You dive both sides by 2 making x = 9.5
The answer is x = 9.5
11. First you need to find how much you need to pay each year. 12,000 x 0.05
you can make it easier by changing it to 120 x 5 = 600
You need to pay that for three years so 600 x 3 = 1800
Plus you need to pay the original money. 12,000 + 1,800 = 13,800
The answer is $13,800
12. First you change kilometers into centimeters. 172 km is 172,000 meters. 172,000 meters is 17,200,000
Then, you need to do 17,200,000 ÷ 500,000 but you can make it simple and do 172 ÷ 5 = 34.4
The answer is 34.4 cm
Answer:
Equation = (x - 6 )² + ( y + 3 )² = 9
Step-by-step explanation:
The circle passes through ( 6, 0) and ( 6 , -6)
They are the coordinates of the diameter.
Using this we can find the centre of the circle.
<u>Find the centre of the circle.</u>
Centre of the circle is the mid- point of (6, 0) and ( 6, -6)
<u>Find the radius of the circle.</u>
Diameter is the distance between the points (6 , 0) and ( 6, - 6)
Therefore,
<u>Standard equation of a circle:</u>
<u></u>
<u></u>
Therefore , equation of the circle ;
