At Barlow school, 4/9 of the 873 students are boys.

Mathematics

2 answers:

wariber [46]3 years ago

4 0

Answer:

Barlow School has the greater number of boys by 178.

saw5 [17]3 years ago

3 0

Answer:

Barlow school by 178

Step-by-step explanation:

→ First let's work out the number of boys at Barlow school

$\frac{4}{9}$ of $873$ $=$ $(873/9)*4$ $=$ $388$

→ There is 388 boys in Barlow school. Now let's work out the number of boys at Willow school. Since we know that $\frac{2}{3}$ of the school is girls, it must mean that the remaining part must be boys so the fraction of boys at Willow school is $\frac{1}{3}$

$\frac{1}{3}$ of $630$ $=$ $(630/3)*1$ $=$ 210

→ The question specifies to say which school has a greater number of boys and we can see Barlow school has more boys and the question says by how many so we take away the totals so 388 - 210 = 178

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Casey ran out of time while taking a multiple-choice test and plans to guess on the last 101010 questions. Each question has 555

Soloha48 [4]

Answer:

There is a 40.96% probability that he answers exactly 1 question correctly in the last 4 questions.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is correct, or it is not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

In this problem we have that:

There are four questions, so n = 4.

Each question has 5 options, one of which is correct. So

What is the probability that he answers exactly 1 question correctly in the last 4 questions?

This is

There is a 40.96% probability that he answers exactly 1 question correctly in the last 4 questions.

7 0

3 years ago