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lyudmila [28]
3 years ago
9

Order the steps to solve the equation log3(x + 2) = log3(2x2 − 1) from 1 to 6

Mathematics
2 answers:
son4ous [18]3 years ago
8 0
Unfortunately, you overlooked the need to share Steps 1-6.

Solve:  (log to the base 3 of)(x+2)= (log to the base 3 of) (2x^2-1).

Use (log to the base 3 of)(x+2) as the exponent of 3 in the equation 3 = 3:

  (log to the base 3 of)(x+2)           (log to the base 3 of) (2x^2-1)
3                                              =  3

This reduces to x+2 = 2x^2 -1, which, in turn, simplifies to 2x^2 - 1 - x - 2 = 0, or 

2x^2 - x - 3 = 0.  You could use the quadratic formula or some other method to solve this for x.  The roots are 3/2 and -1.
PilotLPTM [1.2K]3 years ago
6 0

Answer:


Step-by-step explanation:


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ioda

$225 was earned from the craft sales

and $40 was earned from the play.

Given, During a school carnival, students from the middle school raised money by selling crafts, food, game tickets, and school play admissions.

Of each dollar earned, $0.15 came from games. Craft sales earned 3 times as much as games. Food sales were 4 times the amount earned from the play.

Let the amount earned by play be x,

Now, Games earned = 0.15×500 = $75

Also, crafts earned 3×75 = $225

Now, as play earned x, then food earned 4x.

According to question,

x + 75 + 225 + 4x = 500

5x + 300 = 500

5x = 200

x = 40

So, the amount earned by Play be, $40

and the amount earned by Food be $160.

Hence, $225 was earned from the craft sales

and $40 was earned from the play.

Learn more about Linear Equations here brainly.com/question/24085666

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10 months ago
There is a Saturday performance at a local theater. A theater charges $9 for an adult ticket and $4 for a child ticket. All 1020
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Let x tickets sold be adults, then (1024-x) were of childrens tickets, 9x+(1024-x)4 = 7680. The above equation is for total money solve it you will get x=720 hence, number of adult tickets were 720 and number of child tickets were 300 :)
5 0
3 years ago
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Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)
Arlecino [84]
y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt

By the fundamental theorem of calculus,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}

Now the arc length over an arbitrary interval (a,b) is

\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx

But before we compute the integral, first we need to make sure the integrand exists over it. x^{3/2} is undefined if x, so we assume a\ge0 and for convenience that a. Then

\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)
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3 years ago
Factor completely 6x2 − 11x − 10. (6x 2)(x − 5) (6x − 2)(x 5) (3x 2)(2x − 5) (3x − 2)(2x 5).
madreJ [45]

Factors of the given expression are (2x-5) ,(3x+2)

The given expression is:

6x^2-11x-10

<h3>What is a factor?</h3>

A factor is a number that divides another number leaving no remainder.

we can split the middle term as,

6x^2-15x +4x-10\\

3x(2x-5)+2(2x-5)\\\\(2x-5) (3x+2)

Therefore factors of the given expression are (2x-5) ,(3x+2)

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1 year ago
Write an equation for the translation of y=6\x that has the asymptotes x=-2 and y=-8
Alex
F(x) = 6/x is to be translated down 8 units and left 2 units. It will become
f(x +2) -8

y = 6/(x +2) -8

5 0
3 years ago
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