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Iteru [2.4K]
3 years ago
10

A wind turbine is initially spinning at a constant angular speed. As the wind's strength gradually increases, the turbine experi

ences a constant angular acceleration 0.155 rad/s2. After making 2870 revolutions, its angular speed is 127 rad/s. (a) What is the initial angular velocity of the turbine? (b) How much time elapses while the turbine is speeding up?
Physics
1 answer:
Brums [2.3K]3 years ago
4 0

Answer:

a) Initial angular velocity of the turbine = 102.66 rad/s

b) Time elapsed while the turbine is speeding up = 157 s

Explanation:

a) Considering angular motion of turbine:-

Initial angular velocity, u =  ?

Acceleration , a = 0.155 rad/s²

Final angular velocity, v  = 127 rad/s  

Angular displacement, s = 2π x 2870 = 18032.74 rad

We have equation of motion v² = u² + 2as

Substituting

   v² = u² + 2as

    127² = u² + 2 x 0.155 x 18032.74

    u = 102.66 rad/s

Initial angular velocity of the turbine = 102.66 rad/s

b) We have equation of motion v = u + at

Initial angular velocity, u =  102.66 rad/s

Acceleration , a = 0.155 rad/s²

Final angular velocity, v  = 127 rad/s  

Substituting

  v = u + at

  127  = 102.66 + 0.155 x t = 157 s

Time elapsed while the turbine is speeding up = 157 s

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Answer:

1) A

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6) Incomplete information(picture missing)

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8) F = \frac{mv^{2} }{r}

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = v^{2}

Now, if v is tripled

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