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marusya05 [52]
3 years ago
7

An ice cream truck is going 25m/s to East. It accelerates to 40m/s in the same direction over 3s. What is its acceleration

Physics
2 answers:
lina2011 [118]3 years ago
8 0
40 m/s subtracted by 25m/s is 15.
15 has to be divided by the additional 3s which is 5
The 5 miles and the seconds left behind are 2
Answer: 5m/s2
skad [1K]3 years ago
4 0
Its acceleration is 5m/s2.
The formula for acceleration is Final speed - initial speed/time.
So 40m/s - 25m/s is 15m/s.
15m/s divided by 3s is 5m/s2.
Thus the acceleration is 5m/s2
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A tradesman sharpens a knife by pushing it with a constant force against the rim of a grindstone. The 30-cm-diameter stone is sp
Lorico [155]

Answer:

a. 0.21 rad/s2

b. 2.205 N

Explanation:

We convert from rpm to rad/s knowing that each revolution has 2π radians and each minute is 60 seconds

200 rpm = 200 * 2π / 60 = 21 rad/s

180 rpm = 180 * 2π / 60 = 18.85 rad/s

r = d/2 = 30cm / 2 = 15 cm = 0.15 m

a)So if the angular speed decreases steadily (at a constant rate) from 21 rad/s to 18.85 rad/s within 10s then the angular acceleration is

\alpha = \frac{\Delta \omega}{\Delta t} = \frac{21 - 18.85}{10} = 0.21 rad/s^2

b) Assume the grind stone is a solid disk, its moment of inertia is

I = mR^2/2

Where m = 28 kg is the disk mass and R = 0.15 m is the radius of the disk.

I = 28*0.15^2/2 = 0.315 kgm^2

So the friction torque is

T_f = I\alpha = 0.315*0.21 = 0.06615 Nm

The friction force is

F_f = T_f/R = 0.06615 / 0.15 = 0.441 N

Since the friction coefficient is 0.2, we can calculate the normal force that is used to press the knife against the stone

N = F_f/\mu = 0.441/0.2 = 2.205 N

7 0
3 years ago
Jonah observes the Sun through a special filtered telescope during a total solar eclipse. He sees a red ring and a faint white r
ivann1987 [24]

The answer would be C. chromosphere and corona.

8 0
3 years ago
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The speed of an electromagnetic wave is a constant, 3.0 × 108 m/s. The wavelength of a wave is 0.3 meters. What is the frequency
mojhsa [17]
It would be 1.0 x 10^6 Hz
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3 years ago
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Suppose you wish to construct a motor that produces a maximum torque whose magnitude is 1.7 × 10-2 N·m. The coil of the motor ha
Len [333]

Answer:

86 turns

Explanation:

Parameters given:

Magnetic torque, τ = 1.7 * 10^(-2) Nm

Area of coil, A = 9 * 10^(-4) m²

Current in coil, I = 1.1 A

Magnetic field, B = 0.2 T

The magnetic toque is given mathematically as:

τ = N * I * A * B

Where N = number of turns

To find the number of turns, we make N subject of formula:

N = τ/(I * A * B)

Therefore:

N = (1.7 * 10^(-2)) / (1.1 * 9 * 10^(-4) * 0.2)

N = 85.85 = 86 turns (whole number)

The number of turns must be 86.

3 0
3 years ago
Need help in the middle one
kondor19780726 [428]

Answer:

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