HELP ME PLSS<br> Find g(f(x)). <br> f(x)= x- 3 <br> g(x)= x^2-x- 2

At the beginning of the snowstorm, Olivia had 4 inches of snow on her lawn. The snow then began to fall at a constant rate of 1

Alekssandra [29.7K]

Answer:

For the first one It would be 8 but the second one id k

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Carla, a nurse in the labor and delivery ward of the hospital, is responsible for measuring the

Sonbull [250]

Answer: 50

Explanation

6 0

3 years ago

When 5 is subtracted from the square of a number, the result is 4 times the number. Find the negative solution.

wariber [46]

Answer:

-1

Step-by-step explanation:

You can write it as...

$x^{2} -5=4x$

Carry the 4x

$x^{2} -4x-5=0$

Then use the quadratic formula to solve, since you want to find the negative solution, you don't need to find the positive solution, so we will have

$(4-\sqrt{16+20}) /2=\frac{4-6}{2}=\frac{-2}{2} =-1$

Therefore our answer is -1

8 0

3 years ago

10 cm 10 cm 30 cm. 14.1 cm

Leokris [45]

answer; you

Step-by-step explanation:

5 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

3 years ago

HELP ME PLSS Find g(f(x)). f(x)= x- 3 g(x)= x^2-x- 2