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3 years ago

Two slices of dance famous pizza half 250 cal how many calories are in five slices of pizza

Mathematics

1 answer:

evablogger [386]3 years ago

5 0

Answer:

625

Step-by-step explanation:

Since two slices is 250 calories, let us find how many calories is there in one.

250/2=125 (note, slash signs represents divide sign. When writing down, please write the actual sign.)

Now, we find how many calories are there in 5 pizza slices.

125x5=625

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2 2/5 in kilometers in 3 3/4 minutes unit rate

Mars2501 [29]

Answer:

Step-by-step explanation:

d = r * t Divide both sides by t

r = d / t

d = distance = 2.25 km

t = time = 3 3/4 minutes = 3.75 minutes

r = 2.25 / 3.75

r = 0.6 km / minute

r = 3/5 km / minute

If the units are different than those given, please state them underneath my answer. I'll get to it as soon as I see your comment.

5 0

3 years ago

Find a solution to the linear equation −2x−2y=8 by filling in the boxes with a valid value of x and y.Provide your answer below:

inna [77]

Given

$-2x-2y=8$

To find a solution for the linear equation, the first step is to write the equation in slope-intercept form:

-Pass the x-term to the right side of the equation by applying the opposite operation to both sides of the equal sign:

$\begin{gathered} -2x+2x-2y=8+2x \\ -2y=2x+8 \end{gathered}$

-Divide both sides by -2:

$\begin{gathered} \frac{-2y}{-2}=\frac{2x}{-2}+\frac{8}{-2} \\ y=-x-4 \end{gathered}$

Once you have expressed the equation of the line in slope-intercept form, replace it with any value for x and calculate the corresponding value of y, for example, x=2

$\begin{gathered} y=-(2)-4 \\ y=-2-4 \\ y=-6 \end{gathered}$

One solution for the linear equation is x=2 and y=-6, you can check the solution by replacing the values on the original equation, with both values the result should be 8:

$\begin{gathered} -2x-2y \\ -2\cdot2-2\cdot(-6) \\ -4+12=8 \end{gathered}$

As you can see the values are a valid solution for the linear equation.

So the solution is:

$-2(2)-2(-6)=8$

6 0

1 year ago

Please help me idk this

vichka [17]

Answer:

$\large\boxed{Surface\ Area=63\ cm^2}$

Step-by-step explanation:

We have

square with sides s = 3cm

four triangles with base b = 3cm and height h = 9cm.

The formula of an area of a square:

$A_\square=s^2$

The formula of an area of a triangle:

$A_\triangle=\dfrac{bh}{2}$

Substitute:

$A_\square=3^2=9\ cm^2\\\\A_\triangle=\dfrac{(3)(9)}{2}=\dfrac{27}{2}=13.5\ cm^2$

The Surface Area:

$S.A.=A_\square+4A_\triangle\\\\S.A.=9+4(13.5)=9+54=63\ cm^2$

5 0

3 years ago

What time what equals 115

faust18 [17]

23 times 5 equals 115

5 0

3 years ago

Write an equation of the line that passes through the given point and is parallel to the given line.

Margaret [11]

Answer:

Part 40) $y=-2x+9$

Part 41) $y=5x+6$

Part 42) $y=\frac{2}{3}x+\frac{4}{3}$

Step-by-step explanation:

Remember that

If two lines are parallel, then their slopes are the same

Part 40) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (4,1)

Given line y=-2x+7

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

The slope of the given line is

$m=-2$

step 2

Find the y-intercept b

we have

$m=-2$

$(4,1)$

substitute in the linear equation

$1=(-2)4+b$

solve for b

$b=1+8$

$b=9$

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

$m=-2$

$b=9$

substitute

The equation of the line is

$y=-2x+9$

Part 41) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (0,6)

Given line y=5x-3

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

The slope of the given line is

$m=5$

step 2

Find the y-intercept b

$b=6$ ----> because the y-intercept is the point (0,6) (value of y when the value of x is equal to zero)

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

$m=5$

$b=6$

substitute in the linear equation

$y=5x+6$

Part 42) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (-5,-2)

Given line y=(2/3)x+1

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

The slope of the given line is

$m=\frac{2}{3}$

step 2

Find the y-intercept b

we have

$m=\frac{2}{3}$

$(-5,-2)$

substitute in the linear equation

$-2=(\frac{2}{3})(-5)+b$

solve for b

$-2=-\frac{10}{3}+b$

$b=-2+\frac{10}{3}$

$b=\frac{4}{3}$

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

$m=\frac{2}{3}$

$b=\frac{4}{3}$

substitute

The equation of the line is

$y=\frac{2}{3}x+\frac{4}{3}$

3 0

3 years ago